为什么在C ++中不允许额外的方法限定？ [英] Why in C++ extra method qualification is not allowed?

问题描述

有什么原因我们不能用C ++编写

Is there a reason we can not write in C++

class MyClass
{
public:
    void MyClass::MyMethod();  // <----
}

这样的编译错误，但是有没有原因或者它只是这样发生了？

it gives 'extra qualification' or some such compile error but is there a reason for that or it's just so happened?

推荐答案

因为这是声明的语法;他们声明一个不合格名称在声明范围内具有特定的含义。

Because that's the syntax for declarations; they declare an unqualified name to have a particular meaning within the scope of the declaration.

如果允许范围限定， （指定当前范围）或错误（因为您不能在另一个范围中声明某个内容）。

If a scope qualification were allowed, it would always be either redundant (specifying the current scope) or wrong (since you can't declare something in another scope).

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