在C ++中保存随机数生成器状态11 [英] Saving Random Number Generator State in C++11

问题描述

我想能够在.txt文件中保存随机数生成器的状态并读回。我听说过，使用c ++ 11，这可以使用<<和>>运算符。但是，我不知道我该怎么做。我有一个随机数生成器初始化如下：

I would like to be able to save the state of a random number generator in a .txt file and read it back in. I have heard that with c++11, this can be done using the << and >> operators. However, I'm not sure how exactly I would do this. I have a random number generator initialized as follows:

mt19937 myRandomGenerator(1);
normal_distribution<double> myDistribution(0.0, 1.0);

我想能够在文件save.txt中保存myRandomGenerator的状态。

I would like to be able to save the state of myRandomGenerator in the file save.txt. How would I do thi?

推荐答案

正如所描述的，使用运算符<< / code>并使用 operator>> 读取状态。

It's just as described, write it using operator<< and read the state back in using operator>>.

#include <fstream>
#include <random>
#include <cassert>

int main() {
  std::mt19937 myRandomGenerator(1);

  {
    std::ofstream fout("save.txt");
    fout << myRandomGenerator;
  }

  std::ifstream fin("save.txt");
  std::mt19937 myRandomGeneratorCopy;
  fin >> myRandomGeneratorCopy;
  assert(myRandomGenerator == myRandomGeneratorCopy);
}

这篇关于在C ++中保存随机数生成器状态11的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！