D3日历视图使用关联数组 [英] D3 Calendar View using Associative Array
问题描述
我想创建一个日历视图像这个例子：
编辑3：
我得到步骤1和2解决，这里是jsfiddle链接：
http：// jsfiddle .net / makoto / ARy8d / 9 /
现在尝试找到在同一单元格中添加多值的解决方法
例如，如果我有两个值在数组中有相同的日期，我想添加和查看他们在右边的单元格。然而，现在的代码是什么，如果有两个相同的日期值的值，最后一个覆盖第一个。
任何帮助将做，提前。
这里是解决方案对于数字1和2对于那些谁有类似的问题，我曾经有。希望这将有所帮助。
数组看起来像： BigWordsDates2 = {#Tahrir：[[2012-10-12 20]，[2012-10-13，1]，[2012-10-19，15]]，＃埃及：[[2012-10-01，3] 10-03，2]，[2012-10-04，3]，[2012-10-07，1] 13，2]，[2012-10-14，1]，[2012-10-15，1]，[2012-10-16，1] ，4]，[2012-10-19，5]]};
保存您想要的目标数组值像这样： var tahrir = BigWordsDates2 ['＃Tahrir']
，然后用它覆盖CSV数据。您可以在下面的jsfiddle中找到解决方案的示例。
http://jsfiddle.net/makoto/ARy8d/7/
I want to create a Calendar View Like this example: http://bl.ocks.org/4063318:
Actually i am trying to modify it.
I have an associative array like this: #AdminCourt[["2012-10-02", 2], ["2012-10-09", 2], ["2012-10-16", 1]] #ConstituentAssembly[["2012-10-02", 2], ["2012-10-09", 2], ["2012-10-12", 2], ["2012-10-16", 2]]
I tried filling the calendar like this:
BigWordsDates2.map(function(d) {
return {
date: d[0],
close: d[1]
};
var data = d3.nest()
.key(function(d) { return d.Date; })
.rollup(function(d) { return (d.Close - 0); });
rect.filter(function(d) { return d in data; })
.attr("class", function(d) { return "day " + color(data[d]); })
.select("title")
.text(function(d) { return d + ": " + percent(data[d]); });
});
I know i am not looping through the array and i dont know how i tried for each but it seems that i dont get it correctly.
Here are the stuff that i need ur help with :)
- Loop through the array.( I know how to loop on it but i dont know if there is a way through the D3 class )
- How to Make each cell clickable.
- if i can add MultiValues in a cell ( Probably the keys of the array it depends on the date values).
- How to make the calendar Dynamic Not Set to a certain Range.
Here is the script code i have:
var w = 760,
h = 530;
var cloudwidth = 700, cloudheight=500;
var FunctionCount=0;
var BigWord;
var SmallWord;
var tweets = <?php echo json_encode($Row_Words_Repeated_Relation); ?>;
//var tweets = JSON.parse(TweetsAnalized);
var tweetscounts = JSON.parse('<?php echo $Array_OfCounters_to_json ?>');
var BigWordsDates2 = <?php echo json_encode($Array_OfDates); ?>;
//var BigWordsDates2 = JSON.parse(BigWordsDates);
var OriginalTweets = JSON.parse('<?php echo mysql_real_escape_string($OriginalTweets_to_json) ?>');
var width = 960,
height = 136,
cellSize = 17; // cell size
var day = d3.time.format("%w"),
week = d3.time.format("%U"),
percent = d3.format(".1%"),
format = d3.time.format("%Y-%m-%d");
var color = d3.scale.quantize()
.domain([-.05, .05])
.range(d3.range(11).map(function(d) { return "q" + d + "-11"; }));
var svg = d3.select("body").selectAll("svg")
.data(d3.range(2005, 2015))
.enter().append("svg")
.attr("width", width)
.attr("height", height)
.attr("class", "RdYlGn")
.append("g")
.attr("transform", "translate(" + ((width - cellSize * 53) / 2) + "," + (height - cellSize * 7 - 1) + ")");
svg.append("text")
.attr("transform", "translate(-6," + cellSize * 3.5 + ")rotate(-90)")
.style("text-anchor", "middle")
.text(function(d) { return d; });
var rect = svg.selectAll(".day")
.data(function(d) { return d3.time.days(new Date(d, 0, 1), new Date(d + 1, 0, 1)); })
.enter().append("rect")
.attr("class", "day")
.attr("width", cellSize)
.attr("height", cellSize)
.attr("x", function(d) { return week(d) * cellSize; })
.attr("y", function(d) { return day(d) * cellSize; })
.datum(format);
rect.append("title")
.text(function(d) { return d; });
svg.selectAll(".month")
.data(function(d) { return d3.time.months(new Date(d, 0, 1), new Date(d + 1, 0, 1)); })
.enter().append("path")
.attr("class", "month")
.attr("d", monthPath);
/*d3.csv("dji.csv", function(error, csv) {
var data = d3.nest()
.key(function(d) { return d.Date; })
.rollup(function(d) { return (d[0].Close - d[0].Open) / d[0].Open; })
.map(csv);
rect.filter(function(d) { return d in data; })
.attr("class", function(d) { return "day " + color(data[d]); })
.select("title")
.text(function(d) { return d + ": " + percent(data[d]); });
});*/
BigWordsDates2["#Tahrir"].map(function(d) {
return {
date: d[0],
close: d[1]
};
var data = d3.nest()
.key(function(d) { return d.Date; })
.rollup(function(d) { return (d.Close - 0); });
rect.filter(function(d) { return d in data; })
.attr("class", function(d) { return "day " + color(data[d]); })
.select("title")
.text(function(d) { return d + ": " + percent(data[d]); });
});
function monthPath(t0) {
var t1 = new Date(t0.getFullYear(), t0.getMonth() + 1, 0),
d0 = +day(t0), w0 = +week(t0),
d1 = +day(t1), w1 = +week(t1);
return "M" + (w0 + 1) * cellSize + "," + d0 * cellSize
+ "H" + w0 * cellSize + "V" + 7 * cellSize
+ "H" + w1 * cellSize + "V" + (d1 + 1) * cellSize
+ "H" + (w1 + 1) * cellSize + "V" + 0
+ "H" + (w0 + 1) * cellSize + "Z";
}
d3.select(self.frameElement).style("height", "2910px");
Thanks In Advance and i would really appreciate the help.
EDIT 1:
I tried to work on something like that:
var data1 = d3.entries(BigWordsDates2).forEach(function(d) {
for each (var i in BigWordsDates2[d.key]){
return {
Date: BigWordsDates2[d.key][i][0],
Close: BigWordsDates2[d.key][i][1]
};
};
var data = d3.nest()
.key(function(data1) { return d.Date; })
.rollup(function(data1) { return (d.Close - 0); });
Edit 2: i worked around what was above a bit and this is all i can think of would really need Help, no idea why the values aint appended in the calendar.
var width = 960,
height = 136,
cellSize = 17; // cell size
var day = d3.time.format("%w"),
week = d3.time.format("%U"),
percent = d3.format(".1%"),
format = d3.time.format("%Y-%m-%d");
var color = d3.scale.quantize()
.domain([-.05, .05])
.range(d3.range(11).map(function(d) { return "q" + d + "-11"; }));
var svg = d3.select("body").selectAll("svg")
.data(d3.range(2005, 2015))
.enter().append("svg")
.attr("width", width)
.attr("height", height)
.attr("class", "RdYlGn")
.append("g")
.attr("transform", "translate(" + ((width - cellSize * 53) / 2) + "," + (height - cellSize * 7 - 1) + ")");
svg.append("text")
.attr("transform", "translate(-6," + cellSize * 3.5 + ")rotate(-90)")
.style("text-anchor", "middle")
.text(function(d) { return d; });
var rect = svg.selectAll(".day")
.data(function(d) { return d3.time.days(new Date(d, 0, 1), new Date(d + 1, 0, 1)); })
.enter().append("rect")
.attr("class", "day")
.attr("width", cellSize)
.attr("height", cellSize)
.attr("x", function(d) { return week(d) * cellSize; })
.attr("y", function(d) { return day(d) * cellSize; })
.datum(format);
rect.append("title")
.text(function(d) { return d; });
svg.selectAll(".month")
.data(function(d) { return d3.time.months(new Date(d, 0, 1), new Date(d + 1, 0, 1)); })
.enter().append("path")
.attr("class", "month")
.attr("d", monthPath);
/*d3.csv("dji.csv", function(error, csv) {
var data = d3.nest()
.key(function(d) { return d.Date; })
.rollup(function(d) { return (d[0].Close - d[0].Open) / d[0].Open; })
.map(csv);
rect.filter(function(d) { return d in data; })
.attr("class", function(d) { return "day " + color(data[d]); })
.select("title")
.text(function(d) { return d + ": " + percent(data[d]); });
});*/
d3.entries(BigWordsDates2).map(function(d) {
for each (var i in BigWordsDates2[d.key]){
/*var count =i;
return {
Date: i[0],
Close: i[1]
};*/
rect.filter(function(i) { return i in BigWordsDates2; })
.attr("class", function(i) { return "day " + color(i[0]); })
.select("title")
.text(function(i) { return d.key + ": " + percent(i[1]); });
};
});
function monthPath(t0) {
var t1 = new Date(t0.getFullYear(), t0.getMonth() + 1, 0),
d0 = +day(t0), w0 = +week(t0),
d1 = +day(t1), w1 = +week(t1);
return "M" + (w0 + 1) * cellSize + "," + d0 * cellSize
+ "H" + w0 * cellSize + "V" + 7 * cellSize
+ "H" + w1 * cellSize + "V" + (d1 + 1) * cellSize
+ "H" + (w1 + 1) * cellSize + "V" + 0
+ "H" + (w0 + 1) * cellSize + "Z";
}
d3.select(self.frameElement).style("height", "2910px");
I think am close. any help would be appreciated.
I made a jsfiddle template: http://jsfiddle.net/ARy8d/1/
EDIT 3:
i got Steps 1 and 2 are solved and here is the jsfiddle link: http://jsfiddle.net/makoto/ARy8d/9/
Now trying to find a workaround to add multivalues in same cell
For Example if i have 2 values in array that has the same date i want to add and view them in the right cell. however what the code does right now that if there are 2 values with the same date value the last one overwrites the first one.
Any help will do, thanks in advance.
Here Is The Solution For Number 1 and 2 for those who has the problem similar to the ones i used to have. hope that will helpful.
The array Looks Like That: BigWordsDates2 = {"#Tahrir":[["2012-10-12",20],["2012-10-13",1],["2012-10-19",15]],"#Egypt":[["2012-10-01",3],["2012-10-03",2],["2012-10-04",3],["2012-10-07",1],["2012-10-10",1],["2012-10-13",2],["2012-10-14",1],["2012-10-15",1],["2012-10-16",1],["2012-10-17",4],["2012-10-19",5]]};
Save the Value that Your Targeted array Values you want like that: var tahrir = BigWordsDates2['#Tahrir']
and then overwrite the CSV Data with it. You can Find The example with solution in the jsfiddle below.
http://jsfiddle.net/makoto/ARy8d/7/
这篇关于D3日历视图使用关联数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
