提取Java中两个字符串之间的差异 [英] Extract the difference between two strings in Java

查看:882
本文介绍了提取Java中两个字符串之间的差异的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

您好,我有两个字符串:

  String hear =Hi我的名字是Deepak
+ \\ n
+你好吗?
+\\\

+\\\

+大家怎么样
String dear =Hi我的名字是Deepak
+\\\

+你好吗?
+\\\

+Hey there \\\

+大家怎么样

我想得到在Hey There \\\
。我发现一个方法,但它失败了这种情况:

  static String strDiffChop(String s1,String s2){
if(s1.length()> s2.length()){
return s1.substring(s2.length() - 1);
} else if(s2.length()> s1.length()){
return s2.substring(s1.length() - 1);
} else {
return;
}
}

任何人都可以帮助吗?

解决方案

google-diff- match-patch


Diff Match和Patch库提供强大的算法来执行同步纯文本所需的操作。 p>

Diff:



比较两个纯文本块,并有效地返回一个差异列表。



匹配:



给定一个搜索字符串,在一个纯文本块中找到最好的模糊匹配。



修补程序:



将修补程序列表应用于纯文本。



目前提供Java,JavaScript,Dart,C ++,C#,Objective C,Lua和蟒蛇。无论语言如何,每个库都具有相同的API和相同的功能。所有版本都有全面的测试工具。


有一个行或字差异 wiki页面,其中描述了如何进行逐行差异。


Hi I have two strings :

    String hear = "Hi My name is Deepak"
            + "\n"
            + "How are you ?"
            + "\n"
            + "\n"
            + "How is everyone";
    String dear = "Hi My name is Deepak"
            + "\n"
            + "How are you ?"
            + "\n"
            + "Hey there \n"
            + "How is everyone";

I want to get what is not present in the hear string that is "Hey There \n". I found a method , but it fails for this case :

static String strDiffChop(String s1, String s2) {
    if (s1.length() > s2.length()) {
        return s1.substring(s2.length() - 1);
    } else if (s2.length() > s1.length()) {
        return s2.substring(s1.length() - 1);
    } else {
        return "";
    }
}

Can any one help ?

解决方案

google-diff-match-patch

The Diff Match and Patch libraries offer robust algorithms to perform the operations required for synchronizing plain text.

Diff:

Compare two blocks of plain text and efficiently return a list of differences.

Match:

Given a search string, find its best fuzzy match in a block of plain text. Weighted for both accuracy and location.

Patch:

Apply a list of patches onto plain text. Use best-effort to apply patch even when the underlying text doesn't match.

Currently available in Java, JavaScript, Dart, C++, C#, Objective C, Lua and Python. Regardless of language, each library features the same API and the same functionality. All versions also have comprehensive test harnesses.

There is a Line or word diffs wiki page which describes how to do line-by-line diffs.

这篇关于提取Java中两个字符串之间的差异的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆