Bash脚本查找两个字符串之间的差异 [英] Bash script Find difference between two strings

问题描述

给出以下两个字符串:

"12345"
"1245"

第一个是完整的字符串，第二个是第一个缺少的内容，我希望它返回"3".

Where the first one is the complete string and the second has things missing from the first, I want it to return "3".

再次使用:

"The ball is red"
"The is red"

我想归还球"

我尝试了diff与

diff <(echo "12345") <(echo "1245")

但是diff无法提供所需的输出. comm也不执行我想要的操作.

But diff isn't giving the desired output. comm doesn't do what I want either.

推荐答案

我认为comm是正确的命令:

comm -23 <(tr ' ' $'\n' <<< 'The ball is red') <(tr ' ' $'\n' <<< 'The is red')

或更灵活:

split_spaces() { tr ' ' $'\n' <<< "$1"; }
split_chars() { sed $'s/./&\\\n/g' <<< "$1"; }
comm -23 <(split_spaces 'The ball is red') <(split_spaces 'The is red')
comm -23 <(split_chars 12345) <(split_chars 1245)

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