如何找到在bash两个字符串之间共性？ [英] How do I find common characters between two strings in bash?

问题描述

例如：

s1="my_foo"
s2="not_my_bar"

所期望的结果将是 my_o 。我如何在bash这样做呢？

the desired result would be my_o. How do I do this in bash?

推荐答案

我下面使用的解决方案折叠打破串入每行一个字，排序来对列表排序，通讯来两个字符串最后 TR 比较删除新行字符

My solution below uses fold to break the string into one character per line, sort to sort the lists, comm to compare the two strings and finally tr to delete the new line characters

comm -12 <(fold -w1 <<< $s1 | sort -u) <(fold -w1 <<< $s2 | sort -u) | tr -d '\n'

可替换地，这里是一个纯击溶液（其也保持的字符的顺序）。它遍历第一串并检查每一个字符是第二个字符串中present。

Alternatively, here is a pure Bash solution (which also maintains the order of the characters). It iterates over the first string and checks if each character is present in the second string.

s="temp_foo_bar"
t="temp_bar"
i=0
while [ $i -ne ${#s} ]
do
    c=${s:$i:1}
    if [[ $result != *$c* && $t == *$c* ]]
    then
      result=$result$c
    fi
    ((i++))
done
echo $result

打印： temp_bar

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