G ++编译器不能区分变量和函数具有相同的名称？ [英] G++ compiler cannot distinguish variable and function with the same name?

问题描述

可能重复：

类方法和变量同名，C ++编译错误，而不是在Java？

当我的类成员名称和成员函数名称相同时，G ++编译器会报错。看来只要变量名恰好与函数名相同，编译器就会抱怨。

The G++ compiler would complain when my class member name and member function name are the same. It seems that whenever a variable name happens to be the same as a function name, the compiler would complain.

在Java中，情况并非如此。我只是想知道为什么G ++编译器不能区分变量名称从函数名称，因为函数名称总是带有一对括号。

In Java, it is not the case. I just wonder why the G++ compiler cannot distinguish a variable name from a function name since the function name always comes with a pair of parenthesis.

推荐答案

struct Callable
{
    void operator()() const { }
};

struct Test
{
    void Call() { }
    Callable Call;
};

int main()
{
    Test x;
    x.Call(); // To which 'Call' does this refer?
}

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