将结构中的双指针传递给CUDA [英] Pass double pointer in a struct to CUDA

问题描述

我有以下结构：

 struct Param
{
double** K_RP;                              
};

我想在CUDA中对K_RP执行以下操作

And I wanna perform the following operations on "K_RP" in CUDA

 __global__  void Test( struct Param prop)
       {
       int ix = threadIdx.x;
       int iy = threadIdx.y;
       prop.K_RP[ix][iy]=2.0;
       }

如果prop有以下形式，我应该怎么做cudaMalloc 和cudaMemcpy操作？

If "prop" has the following form, how should I do my "cudaMalloc" and "cudaMemcpy" operations?

int main( )
{
Param prop;
Param cuda_prop;

prop.K_RP=alloc2D(Imax,Jmax);

//cudaMalloc cuda_prop ?

//cudaMemcpyH2D prop to cuda_prop ?

Test<<< (1,1), (Imax,Jmax)>>> ( cuda_prop);   

//cudaMemcpyD2H cuda_prop to prop ?

return (0);

}

推荐答案

这是时不时问。如果你在cuda标签上搜索，你会发现各种各样的答案的例子。以下是一个示例。

Questions like this get asked from time to time. If you search on the cuda tag, you'll find a variety of examples with answers. Here's one example.

• 一般来说，包含在结构或其他对象中的动态分配数据需要特殊处理。此问题/答案说明了为什么以及如何为单指针（<$处理双指针（ ** ）很难，大多数人会推荐展平存储，以便可以通过引用使用单个指针（ * ）来处理。如果你真的想看看双指针（ ** ）如何工作，请查看 this question / answer 。这不是微不足道。

• In general, dynamically allocated data contained within structures or other objects requires special handling. This question/answer explains why and how to do it for the single pointer (*) case.
• Handling double pointers (**) is difficult enough that most people would recommend "flattening" the storage so that it can be handled by reference with a single pointer (*). If you really want to see how the double pointer (**) method works, review this question/answer. It's not trivial.

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