是否可以在原地(破坏性地)修改data.frame? [英] Is it possible to modify a data.frame in-place (destructively)?
问题描述
似乎可以在 data.table
中就地添加/删除列,即而不复制将所有其他列转移到新表中。
It appears that one can add/delete a column to a data.table
in-place, i.e., without copying all the other columns over to a new table.
可以使用一个 data.frame
?
PS。我知道如何添加/删除列功能,即创建一个新的框架,而不修改原始的。
PS. I know how to add/delete columns "functionally", i.e., creating a new frame without modifying the original one.
推荐答案
可以通过 data.table :: set
的引用从 data.frame
中删除或修改现有列。我怀疑你可以添加一个列而不复制。可以向 data.table
中添加列而不复制的原因是 data.table
过度分配记忆。请参见 ?alloc.col
了解详情。
You can delete or modify an existing column from a data.frame
by reference with data.table::set
. I doubt you can add a column without making a copy. The reason that you can add a column to a data.table
without making a copy is that data.table
over allocates memory. See ?alloc.col
for more.
R> library(data.table)
R> data(mtcars)
R> tracemem(mtcars)
[1] "<0x59fef68>"
R> set(mtcars, j="mpg", value=NULL) # remove a column
R> set(mtcars, j="cyl", value=rep(42, 32)) # modify a column
R> untracemem(mtcars)
R> str(mtcars)
'data.frame': 32 obs. of 10 variables:
$ cyl : num 42 42 42 42 42 42 42 42 42 42 ...
$ disp: num 160 160 108 258 360 ...
$ hp : num 110 110 93 110 175 105 245 62 95 123 ...
$ drat: num 3.9 3.9 3.85 3.08 3.15 2.76 3.21 3.69 3.92 3.92 ...
$ wt : num 2.62 2.88 2.32 3.21 3.44 ...
$ qsec: num 16.5 17 18.6 19.4 17 ...
$ vs : num 0 0 1 1 0 1 0 1 1 1 ...
$ am : num 1 1 1 0 0 0 0 0 0 0 ...
$ gear: num 4 4 4 3 3 3 3 4 4 4 ...
$ carb: num 4 4 1 1 2 1 4 2 2 4 ...
与正常的data.frame操作比较
Compare that with normal data.frame operations
R> data(mtcars)
R> tracemem(mtcars)
[1] "<0x6b3ec30>"
R> mtcars[, "mpg"] <- NULL
tracemem[0x6b3ec30 -> 0x84de0c8]:
tracemem[0x84de0c8 -> 0x84de410]: [<-.data.frame [<-
tracemem[0x84de410 -> 0x84de6b0]: [<-.data.frame [<-
R> tracemem(mtcars)
[1] "<0x84dca30>"
R> mtcars[, "cyl"] <- rep(42, 32)
tracemem[0x84dca30 -> 0x84dcc28]:
tracemem[0x84dcc28 -> 0x84dd018]: [<-.data.frame [<-
tracemem[0x84dd018 -> 0x84dff70]: [<-.data.frame [<-
R> untracemem(mtcars)
R> data(mtcars)
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