Python:两个datetimes在几个月的差异 [英] Python: Difference of 2 datetimes in months
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问题描述
我想知道这个差异的确切月份数:
I would like to know how I can have the exact number of months for this difference:
date1 = datetime.strptime(str('2011-08-15 12:00:00'), '%Y-%m-%d %H:%M:%S')
date2 = datetime.strptime(str('2012-02-15'), '%Y-%m-%d')
date2-date1结果
date2-date1 results in
datetime.timedelta(183, 43200)
我想知道确切的月数,在这种情况下应该返回 5 而不是6(因为小时)
I would like to know the exact number of months, in this case it should return 5 and not 6 (because of the hour)
推荐答案
使用日历
找出每个月有多少天,你可以简单地算几个月。
Using calendar
module to find out how many days each month has, you can simply count the months.
from calendar import monthrange
from datetime import datetime, timedelta
def monthdelta(d1, d2):
delta = 0
while True:
mdays = monthrange(d1.year, d1.month)[1]
d1 += timedelta(days=mdays)
if d1 <= d2:
delta += 1
else:
break
return delta
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