计算差异两次之间，因为我们有两个不同的字符串的时间和日期 [英] Calculate diff. between two times given that we have two different strings for time and date

问题描述

我有时间数据分成两个字符串 - 一个字符串日期，一个时间。

我想计算差异。在Java中这样两次。

例如

• 时间1：26/02/2011和11:00 AM


• 时间2：27/02/2011和12:15 AM

差异将是13小时15分钟。 / p>

解决方案

  String str_date1 =26/02/2011; 
 String str_time1 =11:00 AM; 
 
 String str_date2 =27/02/2011; 
 String str_time2 =12:15 AM; 
 
 DateFormat formatter = new SimpleDateFormat（dd / MM / yyyy hh：mm a）; 
日期date1 = formatter.parse（str_date1 ++ str_time1）; 
日期date2 = formatter.parse（str_date2 ++ str_time2）; 
 
 //从每个获取msec，并减去。 
 long diff = date2.getTime（） -  date1.getTime（）; 
 
 System.out.println（Difference In Days：+（diff /（1000 * 60 * 60 * 24）））; 
  

Obs：这只适用于aproximation。请参阅花园路径上的时间丢失。）

I have time data split in two strings - one string for date, and one for time.
I want to calculate the diff. of such two times in Java.
e.g.

• time 1:"26/02/2011" and "11:00 AM"
• time 2:"27/02/2011" and "12:15 AM"

Difference would be like 13 hours 15 minutes.

解决方案

String str_date1 = "26/02/2011";
String str_time1 = "11:00 AM";

String str_date2 = "27/02/2011";
String str_time2 = "12:15 AM" ;

DateFormat formatter = new SimpleDateFormat("dd/MM/yyyy hh:mm a");
Date date1 = formatter.parse(str_date1 + " " + str_time1);
Date date2 = formatter.parse(str_date2 + " " + str_time2);

// Get msec from each, and subtract.
long diff = date2.getTime() - date1.getTime();

System.out.println("Difference In Days: " + (diff / (1000 * 60 * 60 * 24)));

Obs: This is only valid as an aproximation. See Losing Time on the Garden Path.)

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