从两个字典创建一个新列表 [英] Create a new list from two dictionaries

问题描述

这是一个关于Python的问题。我有以下列表：

This is a question about Python. I have the following list of dictionaries:

listA = [
          {"t": 1, "tid": 2, "gtm": 3, "c1": 4, "id": "111"},
          {"t": 3, "tid": 4, "gtm": 3, "c1": 4, "c2": 5, "id": "222"},
          {"t": 1, "tid": 2, "gtm": 3, "c1": 4, "c2": 5, "id": "333"},
          {"t": 5, "tid": 6, "gtm": 3, "c1": 4, "c2": 5, "id": "444"}
        ]

和我想要比较的字典：

dictA = {"t": 1, "tid": 2, "gtm": 3}

我想创建一个匹配 dictA 中所有项目的列表，从 listA 并包含id字段：

I wanted to create a list of dicts that match all the items in dictA from listA and to include the "id" field as well:

listB = [
          {"t": 1, "tid": 2, "gtm": 3, "id": "111"},
          {"t": 1, "tid": 2, "gtm": 3, "id": "333"}
        ]

我试过这样做：

for k in listA:
    for key, value in k.viewitems() & dictA.viewitems():
        print key, value

但它匹配任何 dictA 。

推荐答案

您需要检查交集的长度只要检查，如果dct.viewitems（）&对于任何交集，dictA.viewitems（）将评估为True：

You would need to check the length of the intersection, just checking if dct.viewitems() & dictA.viewitems() would evaluate to True for any intersection :

[dct for dct in listA if len(dct.viewitems() & dictA.viewitems()) == len(dictA)]

或只是检查一个子集，如果dictA的项目是子集每个dict：

Or just check for a subset, if the items from dictA are a subset of each dict:

[dct for dct in listA if dictA.viewitems() <= dct.viewitems()]

或反转寻找 superset ：

 [dct for dct in listA if dct.viewitems() >= dictA.viewitems()]

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