2列表到排序字典回到2列表(多个键值) [英] 2 Lists to Sorted Dictionary back to 2 Lists (Multiple Key Values)
问题描述
date = ['2015/07/13','2015/07/13' 2015/07/07','2015/07/06',...]
#这些日期中有59个
分数= [9.5,13.9,15.5,12.9 ....]这些分数中有59个
dictionary = dict(zip(date,Scores))
d = sorted(dictionary.items())
dte = []
scr = []
在d中:
dte.append(i [0])
scr.append(i [1])$ b $ b
但是,当我打印出这些列表时,长度只有24,而不是59。多个相同的键不会退出。我想知道是否有一个简单的方法来获得所有59个排序的元素回到两个列表。我看了一些类似的其他python答案,但没有一个为我工作。理想情况下,我不想为日期创建对象(除非是最简单的方法),但是当我尝试这样做时,我会收到错误。另外,我在Python 2.7中。
date,Scores = zip (zip(日期,分数)))
I am trying to take two lists: one that contains dates and one that contains scores, then zip them into a dictionary, then sort by the key value, then turn them back in two lists (which are still sorted). The problem that I am encountering is that the dictionary does not keep multiple key values. My code is as follows:
date = ['2015/07/13', '2015/07/13', '2015/07/07', '2015/07/06',...]
#there are 59 of these dates
Scores = [9.5, 13.9, 15.5, 12.9 .... ] #There are 59 of these scores
dictionary = dict(zip(date, Scores))
d = sorted(dictionary.items())
dte = []
scr = []
for i in d:
dte.append(i[0])
scr.append(i[1])
However, when I print out these lists the length is only 24 in length instead of 59, which it should be. The multiple same keys are not coming back out. I was wondering if there was an easy way to get all 59 sorted elements back in two lists. I looked at some of the other python answers that were sort of similar, but none had worked for me. Ideally, I would not like to create objects for the dates (unless that is the easiest method), however when I tried to do so I kept getting errors. Also, I am on Python 2.7.
date, Scores = zip(*sorted(zip(date, Scores)))
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