使用make文件创建目录 [英] Create directories using make file

问题描述

我是一个非常新的makefile，我想使用makefile创建目录。我的项目目录就像这样

I'm a very new to makefiles and i want to create directories using makefile. My project directory is like this

+--Project  
   +--output  
   +--source  
     +Testfile.cpp  
   +Makefile  

我想把所有的对象并输出到相应的输出文件夹。我想在编译后创建一个这样的文件夹结构。

I want to put all the objects and output into the respective output folder. I want to create folder structure which would be like this after compiling.

+--Project
   +--output
     +--debug (or release)
       +--objs
         +Testfile.o
       +Testfile (my executable file)
   +--source
     +Testfile.cpp
   +Makefile

我尝试了几个选项，但无法成功。请帮我制作使用make文件的目录。我发布我的Makefile供您考虑。

I tried with several options, but could not succeed. Please help me to make directories using make file. I'm posting my Makefile for your consideration.

#---------------------------------------------------------------------
# Input dirs, names, files
#---------------------------------------------------------------------
OUTPUT_ROOT := output/

TITLE_NAME := TestProj 

ifdef DEBUG 
    TITLE_NAME += _DEBUG
else
ifdef RELEASE
    TITLE_NAME += _RELEASE
endif
endif


# Include all the source files here with the directory tree
SOURCES := \
        source/TestFile.cpp \

#---------------------------------------------------------------------
# configs
#---------------------------------------------------------------------
ifdef DEBUG
OUT_DIR     := $(OUTPUT_ROOT)debug
CC_FLAGS    := -c -Wall
else
ifdef RELEASE
OUT_DIR     := $(OUTPUT_ROOT)release
CC_FLAGS    := -c -Wall
else
$(error no build type defined)
endif
endif

# Put objects in the output directory.
OUT_O_DIR   := $(OUT_DIR)/objs

#---------------------------------------------------------------------
# settings
#---------------------------------------------------------------------
OBJS = $(SOURCES:.cpp=.o)
DIRS = $(subst /,/,$(sort $(dir $(OBJS))))
DIR_TARGET = $(OUT_DIR)

OUTPUT_TARGET = $(OUT_DIR)/$(TITLE_NAME)

CC_FLAGS +=   

LCF_FLAGS := 

LD_FLAGS := 

#---------------------------------------------------------------------
# executables
#---------------------------------------------------------------------
MD := mkdir
RM := rm
CC := g++

#---------------------------------------------------------------------
# rules
#---------------------------------------------------------------------
.PHONY: all clean title 

all: title 

clean:
    $(RM) -rf $(OUT_DIR)

$(DIR_TARGET):
    $(MD) -p $(DIRS)

.cpp.o: 
    @$(CC) -c $< -o $@

$(OBJS): $(OUT_O_DIR)/%.o: %.cpp
    @$(CC) -c $< -o $@

title: $(DIR_TARGET) $(OBJS)

提前感谢请指导我，如果我也犯了错误。

Thanks in advance. Please guide me if i made any mistakes also.

推荐答案

这样做 - 假设一个类Unix的环境。

This would do it - assuming a Unix-like environment.

MKDIR_P = mkdir -p

.PHONY: directories

all: directories program

directories: ${OUT_DIR}

${OUT_DIR}:
        ${MKDIR_P} ${OUT_DIR}

这必须在顶级目录中运行，否则$ {OUT_DIR}的定义必须相对于运行的位置是正确的。当然，如果您遵循彼得·米勒的递归使用有害的法令 纸，那么你将在顶级目录中运行make。

This would have to be run in the top-level directory - or the definition of ${OUT_DIR} would have to be correct relative to where it is run. Of course, if you follow the edicts of Peter Miller's "Recursive Make Considered Harmful" paper, then you'll be running make in the top-level directory anyway.

我正在玩这个（RMCH）。它需要一些适应我正在使用的软件套件作为测试基础。该套件有十几个单独的程序，源码分布在15个目录中，其中一些共享。但是，有一点关心，可以做到。 OTOH可能不适合新手。

I'm playing with this (RMCH) at the moment. It needed a bit of adaptation to the suite of software that I am using as a test ground. The suite has a dozen separate programs built with source spread across 15 directories, some of it shared. But with a bit of care, it can be done. OTOH, it might not be appropriate for a newbie.

如注释所述，将'mkdir'命令列为目录的动作是错误的。正如评论中所指出的那样，还有其他的方法可以解决不知道如何使输出/调试错误的结果。一个是删除对目录行的依赖。这是因为'mkdir -p'不会产生错误，如果所有要求创建的目录都已经存在。另一个是显示的机制，它只会尝试创建目录（如果不存在）。 修改后的版本是我昨天晚上想到的 - 但是两种技术都可以工作（如果输出/调试存在但是是一个文件而不是一个目录，则这两种技术都有问题）。

As noted in the comments, listing the 'mkdir' command as the action for 'directories' is wrong. As also noted in the comments, there are other ways to fix the 'do not know how to make output/debug' error that results. One is to remove the dependency on the the 'directories' line. This works because 'mkdir -p' does not generate errors if all the directories it is asked to create already exist. The other is the mechanism shown, which will only attempt to create the directory if it does not exist. The 'as amended' version is what I had in mind last night - but both techniques work (and both have problems if output/debug exists but is a file rather than a directory).

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