如何平衡收视率与收视率自己的号码？ [英] How to balance number of ratings versus the ratings themselves?

问题描述

有关学校的项目，我们必须实现一个排名系统。然而，我们计算过，一个愚蠢的排名平均回敬：事情的一个的用户排名第5星将有一个更好的平均的东西188用户评选为4星，而这只是愚蠢

For a school project, we'll have to implement a ranking system. However, we figured that a dumb rank average would suck: something that one user ranked 5 stars would have a better average that something 188 users ranked 4 stars, and that's just stupid.

所以，我想知道如果你们有智能的排名为例算法。它只需要采取在帐户中给出的排名和排名的数目

So I'm wondering if any of you have an example algorithm of "smart" ranking. It only needs to take in account the rankings given and the number of rankings.

谢谢！

推荐答案

下面是一个像样的文章描述背后贝叶斯排名系统理论：

Here's a decent article describing the theory behind a Bayesian Ranking system:

贝叶斯评分 - 如何实现加权排名系统

这篇关于如何平衡收视率与收视率自己的号码？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！