Mongo dbref附加字段在mongoshell中是不可见的。如何显示？ [英] Mongo dbref additional fields are invisible in mongoshell. How to display them?

问题描述

背景：这个问题出现了Doctrine ODM，它使用DBRefs中的_doctrine_class_name字段，在Mongo shell（2.2.2）中是不可见的，当我们必须手动更新记录时，引起了相当的祸患。 >

示例：

  mongoshell>使用testdb; // for safety 
 mongoshell> a = DBRef（layout_block，ObjectId（510a71fde1dc610965000005））; //创建一个dbref 
 mongoshell> a.hiddenfield =whatever//添加通常不在Doctrine的字段
 mongoshell> a //查看它的内容，你不会看到hiddenfield 
 mongoshell> for（k in a）{var val = a [k]; print（k +（+ typeof（val）+）：+ val）; } //你可以看到，如果你遍历它还有更多的东西
 mongoshell> db.testcoll.save（{ref：[a]}）//你可以在一个集合
 mongoshell> db.testcoll.findOne（）; //通常你不会看到它
  

没有像下面的第三个命令（或MongoVue），如果您只使用find（），您将不会知道DBRef中有更多的内容。我没有找到任何可用的修饰符find（）（尝试：toArray，tojson，printjson，toString，hex，base64，pretty，chatty，verbose，...）。

有没有人有方法在mongo shell中详细地显示DBRef内容？

解决方案

Mongo shell是 Mozilla SpiderMonkey （1.7？），具有非常裸的骨骼功能。

来自 MongoDB博客文章的建议外壳将在您的主目录中定义以下检查函数 .mongorc.js p>

  function inspect（o，i）{
 if（typeof i ==undefined）{
i = ; 
} 
 if（i.length> 50）{
 return[MAX ITERATIONS]; 
} 
 var r = []; 
 for（var p in o）{
 var t = typeof o [p]; 
 r.push（i +\+ p +\（+ t +）=>+ 
（t ==object？ + inspect（o [p]，i +）：o [p] +））; 
} 
 return r.join（i +\\\
）; 
} 
  

此外，您可以重新定义DBRef.toString函数，如下所示：

  DBRef.prototype.toString = function（）{
 var r = ['$ ref：'+ tojson $ ref），'$ id：'+ tojson（this。$ id）]; 
 var o = this; 
 for（var p in o）{
 if（p！=='$ ref'&& p！=='$ id'）{
 var t = typeof o [ p]; 
 r.push（''''+ p +'（'+ t +'）：'+ 
（t =='object'？'object：{...}'：o [ p] +''））; 
} 
} 
 return'DBRef（'+ r.join（'，'）+'）'; 
}; 
  

Background: This problem came up with Doctrine ODM, that uses a _doctrine_class_name field in DBRefs that is invisible in the Mongo shell (2.2.2) and caused quite a culprit, when we had to update a record manually.

Example:

mongoshell> use testdb; // for safety
mongoshell> a = DBRef("layout_block", ObjectId("510a71fde1dc610965000005")); // create a dbref
mongoshell> a.hiddenfield = "whatever" // add a field that's normally not there like Doctrine does
mongoshell> a // view it's contents, you won't see hiddenfield
mongoshell> for (k in a) { var val = a[k]; print( k + "(" + typeof(val) + "): " + val ); } // you can see that there's more if you iterate through it
mongoshell> db.testcoll.save({ref: [ a ]}) // you can have it in a collection
mongoshell> db.testcoll.findOne(); // and normally you won't see it

Without an iteration like the third command from below (or MongoVue), you won't ever know there's more in a DBRef if you simply use find(). I have not found any usable modifier for find()(tried: toArray, tojson, printjson, toString, hex, base64, pretty, chatty, verbose, ...).

Has anybody got a method to display DBRef contents verbosely in mongo shell?

解决方案

The Mongo shell is an extension of Mozilla SpiderMonkey (1.7?) and has pretty bare bones functionality.

The suggestion from a MongoDB blog post on the shell is to define the following inspect function in .mongorc.js in your home directory

function inspect(o, i) {
    if (typeof i == "undefined") {
        i = "";
    }
    if (i.length > 50) {
        return "[MAX ITERATIONS]";
    }
    var r = [];
    for (var p in o) {
        var t = typeof o[p];
        r.push(i + "\"" + p + "\" (" + t + ") => " + 
              (t == "object" ? "object:" + inspect(o[p], i + "  ") : o[p] + ""));
    }
    return r.join(i + "\n");
}

Additionally you can redefine the DBRef.toString function as something like:

DBRef.prototype.toString = function () {
    var r = ['"$ref": ' + tojson(this.$ref), '"$id": ' + tojson(this.$id)];
    var o = this;
    for (var p in o) {
        if (p !== '$ref' && p !== '$id') {
            var t = typeof o[p];
            r.push('"' + p + '" (' + t + ') : ' + 
                (t == 'object' ? 'object: {...}' : o[p] + ''));
        }
    }
    return 'DBRef(' + r.join(', ') + ')';
};

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