Java DecimalFormat [英] Java DecimalFormat

问题描述

 DecimalFormat df2 = new DecimalFormat("#.##");
double zipf = 0.23951367781155017; 
String zipt = df2.format(zipf);
System.out.println(zipt);

我得到0,24

这个问题就是我想把它当作一个双重的。但是Double.valueOf（）;方法由于逗号在字符串输出中而失败。任何方式解决这个问题？

The problem with this is then I want to use it as a double. But the Double.valueOf(); method fails due to the comma being there in the string output. Any way to solve this?

推荐答案

对于小数点，您应该创建一个具有英文语言环境的实例，如下所示：

For decimal dot, you should create an instance with english locale like this:

NumberFormat nf = NumberFormat.getNumberInstance(Locale.ENGLISH);
nf.setMinimumFractionDigits(2);
nf.setMaximumFractionDigits(2);
String zipt = nf.format(zipf);
System.out.println(zipt);

我还建议将舍入设置为HALF_UP，因为默认舍入不是我们大多数人期望的： a href =http://docs.oracle.com/javase/1.5.0/docs/api/java/math/BigDecimal.html#ROUND_HALF_EVEN =nofollow> http://docs.oracle.com/ javase / 1.5.0 / docs / api / java / math / BigDecimal.html＃ROUND_HALF_EVEN

I also suggest setting rounding to HALF_UP, because default rounding is not what most of us would expect: http://docs.oracle.com/javase/1.5.0/docs/api/java/math/BigDecimal.html#ROUND_HALF_EVEN

nf.setRoundingMode(RoundingMode.HALF_UP);

这篇关于Java DecimalFormat的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！