如何在Python中使用for循环查找数组中的重复元素? [英] How to find duplicate elements in array using for loop in Python?
问题描述
list_a = [1,2,3,5,6,7, 5,2]
tmp = []
在list_a中为
如果tmp .__包含__(i):
打印i
else:
tmp.append(i)
我已经用上面的代码找到 list_a
中的重复元素。我不想从列表中删除元素。
但是我想在这里使用for循环。
通常C / C ++我们使用这样我猜:
for(int i = 0; i <= list_a (int j = i + 1; j< = list_a.length; j ++)
if(list_a [i] == list_a [j])
print list_a [i]
我们在Python中如何使用?
$在list_a中的
:list_a [1:]中的
....
我尝试了上面的代码。但它会解决错误。我不知道如何增加 j
的价值。
仅供参考,在python 2.7+中,我们可以使用Counter
import collections
x = [ 1,2,3,5,6,7,5,2]
>>> x
[1,2,3,5,6,7,5,2]
>>> y = collections.Counter(x)
>>> y
计数器({2:2,5:2,1:1,3:1,6:1,7:1})
唯一列表
>>>列表(y)
[1,2,3,5,6,7]
发现超过1次的项目
>>> [i for y in y if y [i]> 1]
[2,5]
仅发现一次的项目
>>> [i for y in y if y [i] == 1]
[1,3,6,7]
I have a list with duplicate elements:
list_a=[1,2,3,5,6,7,5,2]
tmp=[]
for i in list_a:
if tmp.__contains__(i):
print i
else:
tmp.append(i)
I have used the above code to find the duplicate elements in the list_a
. I don't want to remove the elements from list.
But I want to use for loop here. Normally C/C++ we use like this I guess:
for (int i=0;i<=list_a.length;i++)
for (int j=i+1;j<=list_a.length;j++)
if (list_a[i]==list_a[j])
print list_a[i]
how do we use like this in Python?
for i in list_a:
for j in list_a[1:]:
....
I tried the above code. But it gets solution wrong. I don't know how to increase the value for j
.
Just for information, In python 2.7+, we can use Counter
import collections
x=[1, 2, 3, 5, 6, 7, 5, 2]
>>> x
[1, 2, 3, 5, 6, 7, 5, 2]
>>> y=collections.Counter(x)
>>> y
Counter({2: 2, 5: 2, 1: 1, 3: 1, 6: 1, 7: 1})
Unique List
>>> list(y)
[1, 2, 3, 5, 6, 7]
Items found more than 1 time
>>> [i for i in y if y[i]>1]
[2, 5]
Items found only one time
>>> [i for i in y if y[i]==1]
[1, 3, 6, 7]
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