ES6中有单线模拟吗？module.exports = require（'./ inner.js'）`？ [英] Is there any one-line analog in ES6 for ES5 `module.exports = require('./inner.js')`?

问题描述

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// nowadays
export from'./inner.js';

我试图这样做，但是babel只允许在es7第1阶段，因为它是< rel =nofollow noreferrer>现在提案href =https://github.com/leebyron/ecmascript-export-default-from。所以现在，我坚持这两行：

 从'./box-sticker.jsx'导入标签; 
导出默认贴纸; 
  

我可以缩短一个吗？

解决方案

您应该可以执行

  export {default as default} from'。 /inner.js'; 
 //甚至
 export {default} from'./inner.js'; 
  

与当前的ES6语义。

我不认为使用ES下一个提案有什么问题，我相信它会使它成为ES7 ES8。

// before
module.exports = require('./inner.js');
// nowadays
export default from './inner.js';

i'm trying to do this, but babel allow it only in es7 stage 1 as it is proposal for now. So for now, im stick to these two lines:

import sticker from './box-sticker.jsx';
export default sticker;

Can I shorter them to one?

解决方案

You should be able to do

export {default as default} from './inner.js';
// or even
export {default} from './inner.js';

with current ES6 semantics.

However I don't think there's anything wrong with using the ES next proposal, I'm pretty confident that it will make it into ES7 ES8.

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