json_decode（）不适用于此有效的JSON字符串 [英] json_decode() does not work with this valid JSON string

问题描述

这是我的应用程序从Postmark接收的JSON字符串，一个入站电子邮件传送服务：

  {
 从：[e-mail]，
FromFull：{
电子邮件：[e-mail]，
名称：杰克
}，
To：\[e-mail]\< [e-mail]>，
ToFull：[
 {
电子邮件：[e-mail]，
名称：[e-mail]
} 
]，
Cc：，
CcFull：[]，
ReplyTo：，
主题：Brussel Sprouts，
MessageID ：a97fb074-338e-48c5-97db-d9c5155e9307，
Date：Sun，2012年12月30日18:10:54 +0000，
MailboxHash：，
TextBody：Are Nice，
HtmlBody：，
Tag：，
标题：[
 {
名称：X-Spam-Checker-Version，
Value：SpamAssassin 3.3.1（2010-03-16）onrs-iad-pm-inbound1.wildbit.com
}，
 {
名称：X-Spam-S t $
价值：否
}，
 {
名称：X-Spam-Score，
价值 0.0
}，
 {
名称：X-Spam-Tests，
值：RCVD_IN_DNSWL_BLOCKED
}，
 {
Name：Received-SPF，
Value：None（no SPF record）identity = mailfrom;客户IP = 209.85.212.175; HELO = mail-wi0-f175.google.com; envelope-from=[e-mail]; receiver = [e-mail]
}，
 {
名称：X-Google-DKIM签名，
价值： v = 1; A = RSA-SHA256; C = relaxed\ /松弛; D = google.com; S = 20120113; h = x-received：from：content-type：content-transfer-encoding：subject：message-id：date：to：mime-version：x-mailer：x-gm-message-state; BH = JrLpPQqTnp0QixED2qZ5 + zepXQXuPLJWqihFECt8uJ4 =; B = EJHac6BaGi3laxnMZZ3Lf\ / ervtavKTG0 + DHXRRCfGH2HSG42wN\ / qIj6IQ0G36NFsjT x2tnYRhj7aBRseky + YEyAF99kUOx\ / p8qaCWo7wN1cf3dTJUrrQu\ / vrdgdXezfheKW49z x4\ / d\ / 8f2bgJN5MvTtZj15WmqZRCDt8\ / QJVZvP7J5hANdxqULgwAJCaCJFU3CTNu66nT + M1tPSDfZwTdNsS70Pna75Y3bRtlJPxXF6gesYhXK\ / cnDbqsCopcAiEc9guMVMnqAjIRu XqBWLft4Bom5H2ViNj5V\ / A3GCmP44h\ / OM1h + h2zBTYJ3fJK4zyluok8K5GIjn9KN1o2w v4eA ==
}，
 {
名称：X接收，
值：由10.180.72.146与SMTP id d18mr51711599wiv。 33.1356891056971;太阳，2012年12月30日10:10:56 -0800（PST）
}，
 {
名称：内容转移编码，
 ：7bit
}，
 {
Name：Message-Id，
Value：< 224B85F9-B9C2-4273-A81C-7C340E8A66B2 @ mydomain.com>
}，
 {
名称：Mime版本，
值：1.0（Mac OS X Mail 6.2 \\ （1499\\））
}，
 {
名称：X-Mailer，
值：苹果邮件（2.1499）
}，
 {
Name：X-Gm-Message-State，
Value：ALoCoQl0eQmrBNRNbe7T06oTeDXcEA3LDLJurR2U0Yj64EyOA2Iy3YL6CyiTodGXtuJHIuMlm5a1
} 
] 
附件：[] 
} 
  

将其复制到任何JSON验证器但是，当我在这个字符串上运行 json_decode（）; 时，在PHP中，它会静默地失败，当运行 echo json_last_error（）; 返回的错误代码是 4 。这对应于语法错误。

通过简单地将 \ 找到 \\我的代码编辑器中的\\\ ，我可以让它工作，但是如何让PHP自动执行此操作？

编辑：如在注释中发现的，上面发布的确切的字符串在从文件读入时可以正常工作，因为PHP不会尝试解析任何反斜杠等。但是，在读取时它似乎正在解析斜杠in file_get_contents（'php：// input）这是什么现在导致我的问题。

解决方案

您可以在变量上执行此操作：

  $ json = str_replace（'\\ '，'\\\\\'，$ json）; 
  

Here is the JSON string my app is receiving from Postmark, an inbound email delivery service:

{
  "From": "[e-mail]",
  "FromFull": {
    "Email": "[e-mail]",
    "Name": "Jack"
  },
  "To": "\"[e-mail]\" <[e-mail]>",
  "ToFull": [
    {
      "Email": "[e-mail]",
      "Name": "[e-mail]"
    }
  ],
  "Cc": "",
  "CcFull": [],
  "ReplyTo": "",
  "Subject": "Brussel Sprouts",
  "MessageID": "a97fb074-338e-48c5-97db-d9c5155e9307",
  "Date": "Sun, 30 Dec 2012 18:10:54 +0000",
  "MailboxHash": "",
  "TextBody": "Are Nice",
  "HtmlBody": "",
  "Tag": "",
  "Headers": [
    {
      "Name": "X-Spam-Checker-Version",
      "Value": "SpamAssassin 3.3.1 (2010-03-16) onrs-iad-pm-inbound1.wildbit.com"
    },
    {
      "Name": "X-Spam-Status",
      "Value": "No"
    },
    {
      "Name": "X-Spam-Score",
      "Value": "0.0"
    },
    {
      "Name": "X-Spam-Tests",
      "Value": "RCVD_IN_DNSWL_BLOCKED"
    },
    {
      "Name": "Received-SPF",
      "Value": "None (no SPF record) identity=mailfrom; client-ip=209.85.212.175; helo=mail-wi0-f175.google.com; envelope-from=[e-mail]; receiver=[e-mail]"
    },
    {
      "Name": "X-Google-DKIM-Signature",
      "Value": "v=1; a=rsa-sha256; c=relaxed\/relaxed;        d=google.com; s=20120113;        h=x-received:from:content-type:content-transfer-encoding:subject         :message-id:date:to:mime-version:x-mailer:x-gm-message-state;        bh=JrLpPQqTnp0QixED2qZ5+zepXQXuPLJWqihFECt8uJ4=;        b=EJHac6BaGi3laxnMZZ3Lf\/ervtavKTG0+DHXRRCfGH2HSG42wN\/qIj6IQ0G36NFsjT         x2tnYRhj7aBRseky+YEyAF99kUOx\/p8qaCWo7wN1cf3dTJUrrQu\/vrdgdXezfheKW49z         x4\/d\/8f2bgJN5MvTtZj15WmqZRCDt8\/QJVZvP7J5hANdxqULgwAJCaCJFU3CTNu66nT+         M1tPSDfZwTdNsS70Pna75Y3bRtlJPxXF6gesYhXK\/cnDbqsCopcAiEc9guMVMnqAjIRu         XqBWLft4Bom5H2ViNj5V\/A3GCmP44h\/OM1h+h2zBTYJ3fJK4zyluok8K5GIjn9KN1o2w         v4eA=="
    },
    {
      "Name": "X-Received",
      "Value": "by 10.180.72.146 with SMTP id d18mr51711599wiv.33.1356891056971;        Sun, 30 Dec 2012 10:10:56 -0800 (PST)"
    },
    {
      "Name": "Content-Transfer-Encoding",
      "Value": "7bit"
    },
    {
      "Name": "Message-Id",
      "Value": "<[e-mail]>"
    },
    {
      "Name": "Mime-Version",
      "Value": "1.0 (Mac OS X Mail 6.2 \\(1499\\))"
    },
    {
      "Name": "X-Mailer",
      "Value": "Apple Mail (2.1499)"
    },
    {
      "Name": "X-Gm-Message-State",
      "Value": "ALoCoQl0eQmrBNRNbe7T06oTeDXcEA3LDLJurR2U0Yj64EyOA2Iy3YL6CyiTodGXtuJHIuMlm5a1"
    }
  ],
  "Attachments": []
}

Copy that into any JSON Validator and you'll see that it is valid.

However, when I run json_decode(); on this string in PHP, it fails silently. When running echo json_last_error(); the returned error code is 4. This corresponds to a Syntax Error.

By simply find-replacing \ to \\ in my code editor, I can get this to work, but how can I get PHP to automatically do this?

EDIT: As discovered in the comments, the exact string I posted above works correctly when read in from a file, as PHP does not try to parse any backslashes etc. However, it appears to be parsing the slashes when read in from file_get_contents('php://input) which is what is now causing me problems.

解决方案

You could do this on the variable:

$json = str_replace('\\', '\\\\', $json);

这篇关于json_decode（）不适用于此有效的JSON字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！