在C中的挑战循环：能不能做到另一种方式？ [英] Loops in C challenge: can it be done another way?

问题描述

你好所有的C专家（请不要拍，我不是C程序员了，但时不时我有持久性有机污染物在我脑海里的问题）

Hi all C experts (please don't shoot, I'm no C programmer anymore but from time to time I have a question that pops in my mind)

我在读另一个问题（<一href="http://stackoverflow.com/questions/4331347/how-to-print-an-entered-string-backwards-in-c-using-only-a-for-loop">How只使用一个for循环）向后C到打印输入的字符串。

I was reading another question (How to print an entered string backwards in C using only a for loop).

在简单，最合乎逻辑的答案是

The "simplest" and most logical answer is

for (x = end; x >= 0; --x) {
    printf("%c", word[x]);
}

不过，我想知道，如果没有一种方法来达到同样的目标，但保持接近原始循环poseted：

But I was wondering if there wasn't a way to achieve the same goal but staying closer to the original loop poseted:

for (x = word[end]; x >= word[0]; x--) {
    printf("%c", x);
}

我不知道够不够C到做出来，但无法通过我们

I don't know enough C to work it out, but couldn't we play with the arrays pointers to loop through

char * wordp;
for(wordp = &word[end]; /*something*/; wordp--){\
   printf("%c", &wordp);
}

PS：我真的不关心，如果它是一个向前或向后循环

P.S.: I don't really care if it is a forwards or backwards loop.

PPS：很抱歉，如果我做的指针明显Ç错误;指出这些问题的评论，我会编辑。 ;）

P.P.S.: Sorry if I made obvious C mistakes in the pointers; point them out in the comment and I'll edit them. ;)

杰森

推荐答案

当然可以。

char *wordp;

for(wordp = word + end; wordp >= word; wordp--){
   printf("%c", *wordp);
}

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