如何保存在Dijkstra算法最短路径 [英] how to save shortest path in dijkstra algorithm
问题描述
因此,首先让我们来定义的Dijkstra算法:
Dijkstra算法发现在一个有向图具有非负边权单源最短路径。
我想知道我怎么能保存的最短路径形式S到T是 Dijkstra算法算法。
我搜索谷歌,但我无法找到一些特别的东西,我改变Dijkstra算法,但我便无法得到答案,所以我们可以节省最短路径形式S到T是 Dijkstra算法?
我知道我的问题是基本的和不专业,但任何帮助,将不胜感激,谢谢您考虑我的问题
So first let's define Dijkstra algorithm:
Dijkstra's algorithm finds single-source shortest paths in a directed graph with non-negative edge weights.
I want to know how can I save the shortest path form s to t with dijkstra algorithm.
I search on google but I couldn't find some thing particular and I change dijkstra algorithm but I could't get answer so can we save shortest path form s to t with dijkstra?
I know my question is basic and unprofessional but any help would be grateful thanks for considering my question
推荐答案
如果你看的从你给了维基百科的链接伪code ,你会看到有一个数组名为 preV []
。该芯片包括,对每个节点的 v 在图中,在 previous 节点的 U 在源节点之间的最短路径<强>取值和 v 。 (此阵也被称为 predecessor 或父阵列。)
If you look at the pseudocode from the Wikipedia link you gave, you'll see an array in there called prev[]
. This array contains, for each node v in the graph, the previous node u in the shortest path between the source node s and v. (This array is also called the predecessor or parent array.)
在换句话说,之间的最短路径的取值和 v 是:
In other words, the shortest path between s and v is:
s -> u -> v
where u = prev[v]
这是该路径的取值为 U 可能有几个节点之间,所以要重建,从取值的路径为 v ,您只需步行回顺使用下面的主伪code中的code段由 preV []
数组定义的路径( 目标是 v ):
The path from s to u might have several nodes in between, so to reconstruct the path from s to v, you just walk back along the path defined by the prev[]
array using the code snippet below the main pseudocode (target is v):
1 S ← empty sequence
2 u ← target
3 while prev[u] is defined: // Construct the shortest path with a stack S
4 insert u at the beginning of S // Push the vertex onto the stack
5 u ← prev[u] // Traverse from target to source
6 end while
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