为什么不用boost :: tie和BOOST_FOREACH? [英] Why doesn't ::boost::tie work with BOOST_FOREACH?
问题描述
我想用 BOOST_FOREACH
遍历一个 boost :: ptr_map
,并碰到这个整洁的解决方案。我宁愿使用这个更好的可读性,而不是其他的解决方案。我写了下面的代码:
boost :: ptr_map< int,std :: string> int2strMap;
总是从模板
int x = 1;
int2strMap.insert(x,new std :: string(one));
int one;
std :: string * two;
BOOST_FOREACH(:: boost :: tie(one,two),int2strMap)
{
std :: cout<<一个<<两个<的std :: ENDL;
$ b然而,这个编译失败,并给我下面的错误(完整):
错误:'operator = no'匹配错误消息有几行,让我知道是否应该粘贴它们。 (操作数类型是boost :: tuples :: detail :: tie_mapper< int,std :: basic_string< char> *,void,void,void,void,void,void> :: type {boost :: tuples :: tuple< int&; std :: basic_string< char> *&; boost :: tuples :: null_type,boost :: tuples :: null_type,boost :: tuples :: null_type,boost :: tuples: :null_type,boost :: tuples :: null_type,boost :: tuples :: null_type,boost :: tuples :: null_type,boost :: tuples :: null_type>}'和'boost :: iterators :: iterator_reference< boost :: ptr_map_iterator< std :: _ Rb_tree_iterator< std :: pair< const int,void *>>,int,std :: basic_string< char> const>> :: type {aka boost :: ptr_container_detail :: ref_pair< int ,std :: basic_string< char> const>}')
BOOST_ FOREACH(:: boost :: tie(one,two),int2strMap)
解决方案为一小撮人工作,我无法弄清楚为什么它不适合我。 (注意:我正在开发一个史前项目,所以坚持使用C ++ 03。g ++ version:4.8.4)
/ p>
解决方案这个问题真的应该是为什么不是
boost :: tie
使用boost :: ptr_map
(或者是取消引用其迭代器的结果)? -BOOST_FOREACH
在这一切中都是相当无辜的。
调查
如果我们查看 Boost版本历史记录,我们可以看到 Tuple 出现在版本1.24.0和指针容器在版本1.33.0中。
$ b元组
github中的相关元组相关代码: b
$ b
- 最近发布:
- 第一版: https://github.com/boostorg/tuple/blob/boost-1.24.0/include /boost/tuple/detail/tuple_basic.hpp
学习代码,我们可以做出如下观察:
cons
[1]
[2]
github中的相关指针容器相关代码: 研究代码,我们可以使以下是观察:元组(和
,它看起来像 cons
)总是有赋值运算符,一个 cons
(ie另一个元组
)
[1]
[2]
或 std :: pair
[1]
[2]
- 其他都没有。
指针容器
std :: pair
,但实际上不是
[1 ]
[2]
[3]
>
我们可以通过只执行一次迭代来消除 BOOST_FOREACH
,而仍然是g等同样的错误:
boost :: tie(one,two)= * int2strMap.begin();
根据我们之前的了解,我们知道这相当于
boost :: tuple< int&; std :: string *&>(one,two)= * int2strMap.begin();
我们也知道 * int2strMap.begin()
将导致 std :: string
引用,或者
由于元组没有赋值操作符,所以建议的代码片段不能用任何现有的Boost版本编译。
解决方法
从实现 boost :: tuple
和 boost :: tie
,我们可以编写一个简单的 reference_pair
模板来存放两个引用,一个一对
(即有成员第一个
和第二个
),以及一个帮助程序 tie
函数,该函数将创建一个 reference_pair
。
示例代码
#include< boost / ptr_container / ptr_map.hpp>
#include< boost / foreach.hpp>
#include< iostream>
命名空间{
模板< class T0,class T1>
struct reference_pair
{
T0&第一;
T1&第二;
$ b reference_pair(T0& t0,T1& t1):first(t0),second(t1){}
template< class U>
reference_pair& operator =(const U& src){
first = src.first;
second = src.second;
return * this;
}
};
模板< class T0,class T1>
inline reference_pair< T0,T1> (t 0,t 1,t 1,t 1,t 1,t 2,t 1,t 1,t 2)
$ b int main()
{
boost :: ptr_map< int,std :: string> int2strMap;
int n(0);
int2strMap.insert(n,new std :: string(one));
int2strMap.insert(++ n,new std :: string(two));
int2strMap.insert(++ n,new std :: string(three));
int one;
std :: string * two;
OOST_FOREACH(tie(one,two),int2strMap)
{
std :: cout<<一个<< << *两个<<的std :: ENDL;
$ / code $ / pre
$ b
控制台输出 h3>
0 one
1 two
2 three
I want to use BOOST_FOREACH
to iterate over a boost::ptr_map
, and came across this neat-looking solution. I would prefer using this for better readability, as against the other solutions given. I wrote the following code:
boost::ptr_map<int, std::string> int2strMap;
int x = 1;
int2strMap.insert(x, new std::string("one"));
int one;
std::string* two;
BOOST_FOREACH(::boost::tie(one, two), int2strMap)
{
std::cout << one << two << std::endl;
}
However, this fails to compile, and gives me the below error (The full error message has several more lines, let me know if I should paste them.):
error: no match for 'operator=' (operand types are 'boost::tuples::detail::tie_mapper<int, std::basic_string<char>*, void, void, void, void, void, void, void, void>::type {aka boost::tuples::tuple<int&, std::basic_string<char>*&, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type, boost::tuples::null_type>}' and 'boost::iterators::iterator_reference<boost::ptr_map_iterator<std::_Rb_tree_iterator<std::pair<const int, void*> >, int, std::basic_string<char>* const> >::type {aka boost::ptr_container_detail::ref_pair<int, std::basic_string<char>* const>}')
BOOST_FOREACH(::boost::tie(one, two), int2strMap)
It appears that the suggested solution works for a handful of people, and I am unable to figure out why it doesn't work for me. What am I doing wrong here?
(Note: I am working on a prehistoric project, so stuck with using C++03. g++ version: 4.8.4)
解决方案 The question really should be "Why doesn't boost::tie
work with boost::ptr_map
(or rather the result of dereferencing its iterator)?" -- BOOST_FOREACH
is quite innocent in all this.
Investigation
If we look at the version history of Boost, we can see that Tuple appears in version 1.24.0 and Pointer Container in version 1.33.0.
Tuple
Relevant tuple related code in github:
- recent release: https://github.com/boostorg/tuple/blob/boost-1.64.0/include/boost/tuple/detail/tuple_basic.hpp
- first release: https://github.com/boostorg/tuple/blob/boost-1.24.0/include/boost/tuple/detail/tuple_basic.hpp
Studying the code, we can make the following observations:
tuple
(and cons
) always had assignment operators taking either a cons
(i.e. another tuple
)
[1]
[2]
or a std::pair
[1]
[2]
-- nothing else.
Pointer Container
Relevant pointer container related code in github:
- recent release: https://github.com/boostorg/ptr_container/blob/boost-1.64.0/include/boost/ptr_container/detail/map_iterator.hpp
- third release: https://github.com/boostorg/ptr_container/blob/boost-1.34.0/include/boost/ptr_container/detail/map_iterator.hpp
- first release: https://github.com/boostorg/ptr_container/blob/boost-1.33.0/include/boost/ptr_container/detail/map_iterator.hpp
Studying the code, we can make the following observations:
- In first two releases (1.33.x), dereferencing the iterator gave us a reference to the value [1] [2]
- Since the third release (1.34.0), we get a
ref_pair
, which somewhat looks like a std::pair
, but really isn't
[1]
[2]
[3]
Conclusion
We can eliminate BOOST_FOREACH
by just doing one iteration, and still get the same error:
boost::tie(one, two) = *int2strMap.begin();
Based on what we learned earlier, we know this is equivalent to
boost::tuple<int&, std::string*&>(one, two) = *int2strMap.begin();
We also know that *int2strMap.begin()
will result in either a std::string
reference, or a ref_pair
.
Since tuple has no assignment operator that would take either of those, the proposed snippet can not compile with any existing version of Boost.
Workaround
Taking inspiration from the implementation of boost::tuple
and boost::tie
, we can write a simple reference_pair
template that holds two references and allows assignment of anything that looks like a pair
(i.e. has members first
and second
), along with a helper tie
function that will create an instance of reference_pair
.
Sample Code
#include <boost/ptr_container/ptr_map.hpp>
#include <boost/foreach.hpp>
#include <iostream>
namespace {
template<class T0, class T1>
struct reference_pair
{
T0& first;
T1& second;
reference_pair(T0& t0, T1& t1) : first(t0), second(t1) {}
template<class U>
reference_pair& operator=(const U& src) {
first = src.first;
second = src.second;
return *this;
}
};
template<class T0, class T1>
inline reference_pair<T0, T1> tie(T0& t0, T1& t1)
{
return reference_pair<T0, T1>(t0, t1);
}
}
int main()
{
boost::ptr_map<int, std::string> int2strMap;
int n(0);
int2strMap.insert(n, new std::string("one"));
int2strMap.insert(++n, new std::string("two"));
int2strMap.insert(++n, new std::string("three"));
int one;
std::string* two;
BOOST_FOREACH(tie(one, two), int2strMap)
{
std::cout << one << " " << *two << std::endl;
}
}
Console Output
0 one
1 two
2 three
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