将C ++代码与'gcc'链接（不含g ++） [英] Linking C++ code with 'gcc' (without g++)

问题描述

大家好：快速的问题：我处于一种只使用'gcc'（不含g ++）来生成C ++可执行文件的情况。原因是我必须将代码提交给自动提交服务器，该服务器无法识别'g ++'（或'c ++'，就此而言）命令。

在我的实验中，当我编译时，gcc运行良好。问题是，当我尝试链接生成的对象文件时，它会变得混乱。现在，基于我从gcc手册页了解的内容（我可能会离开，所以告诉我，如果我是），g ++基本上是gcc，但是它链接了C ++库。

$ b $如果这是真的，我如何（如果可能的话）使用g ++（或c ++）命令显式地链接C ++库而不使用？

编辑：我添加了makefile以更好地说明问题：

  COMPILER = gcc 
 CFLAGS = -Wall -g -x c ++ 
 
＃MODULE COMPILATION 
 model：modules / model.h modules / sources / model.cpp 
 $（COMPILER ）$（CFLAGS）-c modules / sources / model.cpp -o obj / model.o 
 
 algorithms：modules / algorithms.h modules / sources / algorithms.cpp 
 $（COMPILER ）$（CFLAGS）-c modules / sources / algorithms.cpp -o obj / algorithms.o 
 
 io：modules / io.h modules / sources / io.cpp 
 $（COMPILER ）$（CFLAGS）-c modules / sources / io.cpp -o obj / io.o 
 
 stopwatch：modules / stopwatch.h modules / sources / stopwatch.cpp 
 $（COMPILER ） $（CFLAGS）-c modules / sources / stopwatch.cpp -o obj / stopwatch.o 
 
＃EXECUTABLE GENERATION 
 exe：model algorithms io stopwatch 
 $（COMPILER）$ （CFLAGS）main.cpp obj / model.o obj / algorithms.o obj / io.o obj / stopwatch.o -o bin / process 
 
＃DEFAULT TEST CASE 
 run：exe 
 ./bin/process -i data / nasa_small.log -a data / nasa_small.access -s data / nasa_small.stack 
 
＃CLEANING ROUTINE 
 clean：
 rm -f obj / * 
  

解决方案

标准c ++库，其中 -l <​​/ code>标志为gcc：

  gcc cplusplus .o -lstdc ++ -o myexe 
  




Hi all: quick question: I'm in a situation where it would be useful to generate my C++ executable using only 'gcc' (without g++). Reason for this is that I have to submit the code to an automatic submission server which doesn't recognize the 'g++' (or 'c++', for that matter) command.

In my experiments, while I'm compiling gcc works well. Problem is, when I try to link the generated object files it gets messed up. Now, based on what I understood from the gcc man page (I may be way off, so tell me if I am), g++ is basically gcc, but it links the C++ library.

If this is true, how can I (if possible) explicitly link the C++ library without using the g++ (or c++) command?

EDIT: I'm adding the makefile to better illustrate the problem:

COMPILER = gcc
CFLAGS = -Wall -g -x c++

# MODULE COMPILATION
model: modules/model.h modules/sources/model.cpp
    $(COMPILER) $(CFLAGS) -c modules/sources/model.cpp -o obj/model.o

algorithms: modules/algorithms.h modules/sources/algorithms.cpp
    $(COMPILER) $(CFLAGS) -c modules/sources/algorithms.cpp -o obj/algorithms.o

io: modules/io.h modules/sources/io.cpp
    $(COMPILER) $(CFLAGS) -c modules/sources/io.cpp -o obj/io.o

stopwatch: modules/stopwatch.h modules/sources/stopwatch.cpp
    $(COMPILER) $(CFLAGS) -c modules/sources/stopwatch.cpp -o obj/stopwatch.o

# EXECUTABLE GENERATION
exe: model algorithms io stopwatch
    $(COMPILER) $(CFLAGS) main.cpp obj/model.o obj/algorithms.o obj/io.o obj/stopwatch.o -o bin/process

# DEFAULT TEST CASE
run: exe
    ./bin/process -i data/nasa_small.log -a data/nasa_small.access -s data/nasa_small.stack

# CLEANING ROUTINE
clean:
    rm -f obj/*

解决方案

You can link the standard c++ library with the -l flag to gcc:

gcc cplusplus.o -lstdc++ -o myexe

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