geom_tile热图以不同的高填充颜色为基础 [英] geom_tile heatmap with different high fill colours based on factor

问题描述

我有兴趣在 ggplot2 中用 geom_tile 构建一个使用基于因子的不同渐变高颜色的热图。

I'm interested in building a heatmap with geom_tile in ggplot2 that uses a different gradient high color based on a factor.

下面的图表根据 xy_type 创建了单个图块为蓝色或红色的情节，但没有渐变。

The plot below creates the plot where the individual tiles are colored blue or red based on the xy_type, but there is no gradient.

ggplot() + 
  geom_tile(data=mydata, aes(x=factor(myx), y=myy, fill=factor(xy_type))) + 
  scale_fill_manual(values=c("blue", "red"))

下面的图不使用 xy_type 因子来选择颜色，但是我得到了一个基于 xy_avg_value 。

The plot below does not use the xy_type factor to choose the color, but I get a single group gradient based on the xy_avg_value.

ggplot() + 
  geom_tile(data=mydata, aes(x=factor(myx), y=myy, fill=xy_avg_value))

融合这两块地块？我可以使用 facet_grid（xy_type〜。）来创建此数据的单独绘图，并使用渐变。因为这最终将成为一个地图（x〜y坐标），所以我想找到一种方法来在单个 geom_tile 地图中显示不同的渐变。

Is there a technique to blend these two plots? I can use a facet_grid(xy_type ~ .) to create separate plots of this data, with the gradient. As this is ultimately going to be a map (x~y coordinates), I'd like to find a way to display the different gradient together in a single geom_tile map.

推荐答案

一般而言， ggplot2 不允许多种比例的单一类型（即多种颜色或填充所以我怀疑这不是（很容易）。

In general, ggplot2 does not permit multiple scales of a single type (i.e. multiple colour or fill scales), so I suspect that this isn't (easily) possible.

我能想到的最接近的近似值是：

The best nearest approximation I can come up with is this:

df <- data.frame(expand.grid(1:5,1:5))
df$z <- runif(nrow(df))
df$grp <- rep(letters[1:2],length.out = nrow(df))

ggplot(df,aes(x = Var1,y = Var2,fill = factor(grp),alpha = z)) + 
    geom_tile() + 
    scale_fill_manual(values = c('red','blue'))

但是要得到一个合理的传说很难。

But it's going to be tough to get a sensible legend.

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