提取两个字符串之间的特定字符串并列出所需的内容 [英] Extract specific string between two strings and list the required content

问题描述

如何找到字符串可用的块名称？

server.conf文件

  server_pool奇数{
 0：server1：是：profile_server1：192.168.1.1,192.168.1.2; 
 1：server3：是：profile_server3：192.168.1.5,192.168.1.6; 
} 
 
 server_pool甚至{
 0：server2：是：profile_server2：192.168.1.3,192.168.1.4; 
 1：server4：是：profile_server4：192.168.1.7,19​​2.168.1.8; 
} 
 
 #server_pool甚至{
＃0：server1：是：profile_server1：192.168.1.1,192.168.1.2; 
＃1：server3：是：profile_server3：192.168.1.5,192.168.1.6; 
 
  

注意： -

1. server_pool是一个静态字符串


2. pool_name可以是任何不含空格的字符串。
   

要求

1. 需要通过提供的服务器主机名作为输入来查找pool_name，例如服务器{1,2,3}，并将其存储在变量中
   

例如

如果需要查找server1属于哪个block / stanza。在给定的用例中它属于odd，所以存储变量为POOLNAME = odd

解决方案

  grep -oP'^ server \s\K [ ^] + | ^ [^＃] \ s + \ d +：\ K [^：] +'inputfile 
 pool0 
 server1 
 server2 
 pool1 
 server3 
 server4 
  

how to find the block name in which the string available ?

server.conf file

server_pool odd {
    0:server1:yes:profile_server1:192.168.1.1,192.168.1.2;
    1:server3:yes:profile_server3:192.168.1.5,192.168.1.6;
}

server_pool even {
    0:server2:yes:profile_server2:192.168.1.3,192.168.1.4;
    1:server4:yes:profile_server4:192.168.1.7,192.168.1.8;
}

#server_pool even {
#    0:server1:yes:profile_server1:192.168.1.1,192.168.1.2;
#    1:server3:yes:profile_server3:192.168.1.5,192.168.1.6;
#}

Notes:-

1. "server_pool" is a static string
2. "pool_name" can be any string without spaces
3. "if a line has # in it ignore it

Requirement

1. Need to find the "pool_name" by the provided server hostname as input i.e server{1,2,3,} and store it in a variable

for example

if need to find server1 belongs to which block/ stanza. in the given use case it belongs to odd, so store variable as POOLNAME=odd

解决方案

grep -oP '^server\s\K[^ ]+|^[^#]\s+\d+:\K[^:]+' inputfile
pool0
server1
server2
pool1
server3
server4

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