将十六进制数据读入较少 [英] Read hex data into less

问题描述

我想给一个大数据文件< less -s -M + Gg ，这样读取给定数据的当前读取少于-s -M +千兆克。

While循环示例（请参阅ntc2的答案） /stackoverflow.com/a/19871578/54964\">here 。
用一个二进制文件替换 yes ，二进制文件转换为二进制ascii和十六进制：

 ，同时读取-u 10 p || [[-n $ p]]; do 
 hexdump -e'/ 4％08x\\\
'{$ p} \ 
 \ 
 | less -s -M + Gg 
 done 10< / Users / masi / Dropbox / 7-8 \：2015 / r3.raw 
  

其中循环基于此主题此处。

你怎么能把这些数据读得更少？

解决方案

我不明白这个例子的细节，但我想你想把少于循环外部，如下所示：

  while read -u 10 p || [[-n $ p]]; 
 hexdump -e'/ 4％08x\\\
'{$ p} 
 done 10   

I want to give a big data file to less -s -M +Gg such that read current given data in less -s -M +Gg.

While-loop example (see ntc2's answer)

Less command explained here. Replacing the yes by a binary file which is converted to binary ascii and hex:

while read -u 10 p || [[ -n $p ]]; do
    hexdump -e '/4 "%08x\n"' {$p}                       \
                                                        \
    | less -s -M +Gg
done 10</Users/masi/Dropbox/7-8\:2015/r3.raw

where the looping is based on this thread here.

How can you read such data into less?

解决方案

I don't understand the details of the example, but I think you want to put the less outside of the loop, like this:

while read -u 10 p || [[ -n $p ]]; do
    hexdump -e '/4 "%08x\n"' {$p}
done 10</Users/masi/Dropbox/7-8\:2015/r3.raw | less -s -M +Gg

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