在C中将十六进制转换为字符串？ [英] Converting hex to string in C?

问题描述

你好我正在使用digi dynamic c。我试图将其转换为字符串

  char readingreg [4]; 
 readingreg [0] = 4a; 
 readingreg [1] = aa; 
 readingreg [2] = aa; 
 readingreg [3] = a0; 
  

目前，当我执行 printf 如下所示：

  printf（This is element 0：％x \\\
，readingreg [0]）; 
  

但我想要这个字符串，所以我可以使用 printf $> $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $'$> printf（这是元素0：％s \ n，readingreg [0]） ;

我必须通过TCP / IP端口发送readreg数组，我需要将它作为串。我似乎无法将其转换为字符串。谢谢你的帮助。
另外如果有人可以告诉我如何一次完成每个元素而不是整个数组，那就没问题了，因为只会有4个元素。

解决方案

0xaa 当plain char 签名时溢出，使用 unsigned char ：

  #include< stdio.h> 
 
 int main（void）
 {
 unsigned char readingreg [4]; 
 readingreg [0] = 0x4a; 
 readingreg [1] = 0xaa; 
 readingreg [2] = 0xaa; 
 readingreg [3] = 0xa0; 
 char temp [4]; 
 
 sprintf（temp，％x，readingreg [0]）; 
 printf（这是元素0：％s \ n，temp）; 
返回0; 
} 
  

Hello I am using digi dynamic c. I am trying to convert this in to string

char readingreg[4];
readingreg[0] = 4a;
readingreg[1] = aa;
readingreg[2] = aa;
readingreg[3] = a0;

Currently when I do printf statements it has to be like this:

printf("This is element 0: %x\n", readingreg[0]);

But I want this in string so I can use printf statement like this

  printf("This is element 0: %s\n", readingreg[0]);

I am essentialy sending the readingreg array over TCP/IP Port, for which I need to have it as string. I cant seem to be able to convert it into string. Thanks for your help. Also if someone can tell me how to do each element at a time rather than whole array, that would be fine to since there will only be 4 elements.

解决方案

0xaa overflows when plain char is signed, use unsigned char:

#include <stdio.h>

int main(void)
{
    unsigned char readingreg[4];
    readingreg[0] = 0x4a;
    readingreg[1] = 0xaa;
    readingreg[2] = 0xaa;
    readingreg[3] = 0xa0;
    char temp[4];

    sprintf(temp, "%x", readingreg[0]);
    printf("This is element 0: %s\n", temp);
    return 0;
}

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