在C＃中将十六进制字符串转换为其数值 [英] Convert hexadecimal string to its numerical values in C#

问题描述

我的表单上有一个文本框。我想将0x31作为字符串写入我的文本框，然后当我单击按钮时，我想将此字符串转换为0x31作为十六进制值。

i have a text box on my form. I want to write "0x31" as a string to my textbox and then when i clicked a button, i want to convert this string to 0x31 as a hexadecimal value.

我可以将此字符串转换为十六进制值吗？

How can i convert this string to hexadecimal value?

推荐答案

string hexValues = "48 65 6C 6C 6F 20 57 6F 72 6C 64 21";
string[] hexValuesSplit = hexValues.Split(' ');
foreach (String hex in hexValuesSplit)
{
    // Convert the number expressed in base-16 to an integer.
    int value = Convert.ToInt32(hex, 16);
    // Get the character corresponding to the integral value.
    string stringValue = Char.ConvertFromUtf32(value);
    char charValue = (char)value;
    Console.WriteLine("hexadecimal value = {0}, int value = {1}, char value = {2} or {3}",
                    hex, value, stringValue, charValue);
}

示例来自： http://msdn.microsoft.com/en-us/library/bb311038.aspx

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