休眠标准API'选择' [英] Hibernate criteria api 'Select in'

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本文介绍了休眠标准API'选择'的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

是否有可能通过hibernate critiria api创建'select in'查询?

示例:
我有两张表,分别是1: n关系,公司和部门

  select * from公司c其中c.id in(从部门选择company_id d 
其中d.departmentname ='HR'和d.location ='xyz')


解决方案

您可以使用此DetachedCriteria

  DetachedCriteria subCriteria = DetachedCriteria.forClass(Departament.class); 
subCriteria.add(Property.forName(departmentname).eq(HR));
subCriteria.add(Property.forName(location).eq(xyz));
subCriteria.setProjection(Projections.property(company_id));

DetachedCriteria标准= DetachedCriteria.forClass(Company.class);
criteria.add(Property.forName(id)。in(subCriteria));


is it possible to create a 'select in'-query with the hibernate critiria api ?

Example : I have two tables in a 1:n relation, company and department

select * from company c where c.id in (select company_id from department d 
where d.departmentname = 'HR' and d.location = 'xyz')

解决方案

You can use for this DetachedCriteria

DetachedCriteria subCriteria= DetachedCriteria.forClass(Departament.class);
     subCriteria.add(Property.forName("departmentname ").eq("HR"));
     subCriteria.add(Property.forName("location ").eq("xyz"));
     subCriteria.setProjection(Projections.property("company_id "));

DetachedCriteria criteria = DetachedCriteria.forClass(Company.class);
     criteria.add(Property.forName("id").in(subCriteria));

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