在休眠标准中达到3级标准 [英] go up to 3 level dephth in hibernate criterion

问题描述

我使用休眠标准来获取结果。在这里，我提供了持久化类的演示设计。

  A类{
 private B b; 
} 
 B类{
 private C c; 
} 
类别C {
 private Long val; 
 
 
 
 $ b $ p 
 $ b 
假设这些是hibernate持久性类，我不写所有映射注释数据库。
 
 
现在我的问题是我想根据 C类的val属性的值检索 A类的结果 strong>。
 
 
 
我尝试使用它获取它，
  Criteria c = Restrictions.eq（bcval，value）; 
列表l = c.list; 
  
它显示无法解析属性。我搜索了一下，并且知道标准不会达到这个深度。我不想转移到HQL。任何想法?? 
解决方案
 
  Criteria c = session.createCriteria（A.class）
 .createCriteria（b）
 .createCriteria（c）
 .add（Restrictions.eq（val，value））; 
 
列表l = c.list; 
  
 
i am using hibernate criterion for fetching results. Here with i provided demo design of my persistence class.
Class A{
private B b;
}
Class B{
private C c;
}
Class C{
private Long val;
}
assume these are the hibernate persistence classes i am not writing all annotations of mapping with database.

now my problem is i want to retrieve results of Class A according to the value of Class C's val property.

i tried to fetch it using,
Criteria c = Restrictions.eq("b.c.val", value);
List l = c.list;
it shows could not resolve property. i searched and came to know criteria wont work up to this much depth. i don't want shift to HQL. any idea??
解决方案
Criteria c = session.createCriteria(A.class)
    .createCriteria("b")
    .createCriteria("c")
    .add(Restrictions.eq("val", value));

List l = c.list;


                        
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