C ++打开与ShellExecute的链接 [英] C++ open link with ShellExecute

问题描述

如果我这样写：

    ShellExecute(NULL, "open", "www.google.com", NULL, NULL, SW_SHOWNORMAL);

一切都没问题就像它一样。

Everything's okay and is as it has to be.

但我希望用户可以输入他想去的链接。

But I want so that user could enter a link where he wants to go.

std::cout<<"Enter the link: ";
            char link;
            std::cin>>link;
        ShellExecute(NULL, "open", link, NULL, NULL, SW_SHOWNORMAL);

在这种情况下，我得到一个从'char'到'const的无效转换CHAR * 错误。

In this case I get an invalid conversion from 'char' to 'const CHAR* error.

那么，有没有办法正确地做到这一点？

So, is there a way to do this properly?

推荐答案

您的代码只能获得一个字符作为链接。您需要使链接成为能够保存链接值的类型，并且还要读取stdio。使链接成为std :: string将执行此操作，但是您需要处理它如何传递给ShellExecute

Your code only gets one character in as the link. You need to make link a type able to hold the value of the link and also read stdio in. Making link a std::string will do this but then you need to take care of how it is passed to ShellExecute

std::cout<<"Enter the link: ";
std::string link;
std::cin>>link;
ShellExecute(NULL, "open", link.c_str(), NULL, NULL, SW_SHOWNORMAL);

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