访问由std :: shared_ptr包装的类的运算符重载 [英] accessing operator overloading of class which is wrapped by std::shared_ptr
问题描述
我的想法是,我想要一个由 std :: shared_ptr
包装的类,仍然可以使用
就像它们不是指针一样,例如,在我的类
中定义的operator =仍然可以在我的类被 std :: shared_ptr
包装之后使用。
the idea is that I want a class which is wrapped by std::shared_ptr
, can still be used
just like they weren't a pointer, for example the operator= which was defined in my class
can still be used after my class is wrapped by std::shared_ptr
.
例如
template <class Ty> class shared_ptr_proxy : public std::shared_ptr<Ty> {
public:
template<class Other> shared_ptr_proxy& operator=(const Other& rhs)
{
(*this->get()) = rhs;
return *this;
}
template<class Other> explicit shared_ptr_proxy(Other * ptr)
: std::shared_ptr<Ty>(ptr){};
};
// usage :
shared_ptr_proxy<float> obj = shared_ptr_proxy<float>(new float);
obj = 3.14;
它的工作,但是有一种方法我不需要创建 shared_ptr_proxy
或
从 std :: shared_ptr
继承一个类?
its work, but is there a way that i don't need to create shared_ptr_proxy
or
inheriting a class from std::shared_ptr
?
和
如果我喜欢这个,是否需要注意?
if I do like this, is there a caveat that i should take care of?
推荐答案
这取决于你想要代理的内容。完整代理可能会使它看起来完全像您拥有的值,因此您需要提供转换运算符。
It depends on what you want the proxy for. A full proxy might make it look entirely like you had the value, so you'd provide the conversion operators.
在这种情况下,从 shared_ptr
继承可能不是一个好主意,因为你可能是继承你想要依赖隐式转换的函数。
In such case, it might not be a good idea to inherit from shared_ptr
, though, because you might be inheriting functions that you want to rely on the implicit conversions instead.
比较排序对项目的排序方式:
Compare how sorting orders the items:
#include <memory>
#include <vector>
#include <algorithm>
#include <iostream>
template <class Ty> class shared_ptr_proxy {
std::shared_ptr<Ty> ptr;
public:
template<class Other> explicit shared_ptr_proxy(Other * p)
: ptr(std::shared_ptr<Ty>(p)){};
template<class Other> shared_ptr_proxy& operator=(const Other& other)
{
*ptr = other;
return *this;
}
operator Ty& () { return *ptr; }
operator const Ty& () const { return *ptr; }
};
int main()
{
std::vector<shared_ptr_proxy<int> > vec {
shared_ptr_proxy<int>(new int(10)),
shared_ptr_proxy<int>(new int(11)),
shared_ptr_proxy<int>(new int(9))
};
vec.back() = 8; //use assignment
std::sort(vec.begin(), vec.end()); //sort based on integer (not pointer) comparison
for (unsigned i = 0; i != vec.size(); ++i) {
std::cout << vec[i] << ' '; //output stored values
}
}
#include <memory>
#include <vector>
#include <algorithm>
#include <iostream>
template <class Ty> class shared_ptr_proxy : public std::shared_ptr<Ty> {
public:
template<class Other> explicit shared_ptr_proxy(Other * p)
: std::shared_ptr<Ty>(p){};
template<class Other> shared_ptr_proxy& operator=(const Other& other)
{
*this->get()= other;
return *this;
}
operator Ty& () { return *this->get(); }
operator const Ty& () const { return *this->get(); }
};
int main()
{
std::vector<shared_ptr_proxy<int> > vec {
shared_ptr_proxy<int>(new int(10)),
shared_ptr_proxy<int>(new int(11)),
shared_ptr_proxy<int>(new int(9))
};
vec.back() = 8; //the only thing that works
std::sort(vec.begin(), vec.end()); //sort based on pointer values
for (unsigned i = 0; i != vec.size(); ++i) {
std::cout << vec[i] << ' '; //outputs addresses
}
}
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