检查NSString是否包含任何数字，且长度至少为7个字符 [英] Check if NSString contains any numbers and is at least 7 characters long

问题描述

所以我想我需要一个正则表达式语句才能做到这一点，但我还没有用目标c做任何正则表达式，而且我还没有在一年内编写正则表达式语句。

So I imagine that I need a regex statement to do this but I haven't had to do any regex with objective c yet, and I haven't written a regex statement in like a year.

我认为应该是（（？=。* [0-9]）。{7,1000}）

I think it should be like ((?=.*[0-9]).{7,1000})

如何我把它放到一个客观的c字符串比较中并评估结果？

How do I put this into an objective c string comparison and evaluate the results?

我的正则表达式是否正确？

Also is my regex correct?

推荐答案

虽然正则表达式可能有效，但还有另一种方法：

While a regular expression would probably work, there is another approach:

NSString *str = // some string to check for at least one digit and a length of at least 7
if (str.length >= 7 && [str rangeOfCharacterFromSet:[NSCharacterSet decimalDigitCharacterSet]].location != NSNotFound) {
    // this matches the criteria
}

此代码实际上检查不仅仅是0-9。它也处理来自其他语言的数字。如果你真的只想要0-9然后替换：

This code actually checks more than just 0-9. It handles digits from other languages too. If you really just want 0-9 then replace:

[NSCharacterSet decimalDigitCharacterSet]

with：

[NSCharacterSet characterSetWithCharactersInString:@"0123456789"];

这篇关于检查NSString是否包含任何数字，且长度至少为7个字符的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！