是否拥有String :: chars的自有版本？ [英] Is there an owned version of String::chars?

问题描述

以下代码无法编译：

use std::str::Chars;

struct Chunks {
    remaining: Chars,
}

impl Chunks {
    fn new(s: String) -> Self {
        Chunks {
            remaining: s.chars(),
        }
    }
}

错误是：

error[E0106]: missing lifetime specifier
 --> src/main.rs:4:16
  |
4 |     remaining: Chars,
  |                ^^^^^ expected lifetime parameter

Chars 不拥有它迭代的字符，它不能超过& str 或字符串它是从...创建。

Chars doesn't own the characters it iterates over and it can't outlive the &str or String it was created from.

是否拥有 Chars 的自有版本，不需要生命周期参数，或者我是否需要保留 Vec< char> 和我自己的索引？

Is there an owned version of Chars that does not need a lifetime parameter or do I have to keep a Vec<char> and an index myself?

推荐答案

std :: vec :: IntoIter 在某种意义上是每个迭代器的拥有版本。

std::vec::IntoIter is an owned version of every iterator, in a sense.

use std::vec::IntoIter;

struct Chunks {
    remaining: IntoIter<char>,
}

impl Chunks {
    fn new(s: String) -> Self {
        Chunks {
            remaining: s.chars().collect::<Vec<_>>().into_iter(),
        }
    }
}

Playground link

下行是额外的分配和空间开销，但我不知道您特定案例的迭代器。

Downside is additional allocation and a space overhead, but I am not aware of the iterator for your specific case.

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