非静态方法无法从静态上下文中引用 [英] non static method cannot be referenced from a static context

问题描述

首先是一些代码：

import java.util.*;
//...

class TicTacToe 
{
//...

public static void main (String[]arg) 
{ 

    Random Random = new Random() ; 
    toerunner () ; // this leads to a path of 
                   // methods that eventualy gets us to the rest of the code 
} 
//... 

public void CompTurn (int type, boolean debug) 
{ 
//...

        boolean done = true ; 
        int a = 0 ; 
        while (!done) 
        { 
            a = Random.nextInt(10) ;
            if (debug) { int i = 0 ; while (i<20) { System.out.print (a+", ") ; i++; }} 
            if (possibles[a]==1) done = true ; 
        } 
        this.board[a] = 2 ; 


}
//...

} //to close the class 

以下是错误消息：

TicTacToe.java:85: non-static method nextInt(int) cannot be referenced from a static context
            a = Random.nextInt(10) ;
                      ^

究竟出了什么问题？该错误消息非静态方法无法从静态上下文引用是什么意思？

What exactly went wrong? What does that error message "non static method cannot be referenced from a static context" mean?

推荐答案

您使用 nextInt > Random.nextInt 。

You are calling nextInt statically by using Random.nextInt.

相反，创建一个变量， Random r = new Random（）; 然后拨打 r.nextInt（10）。

Instead, create a variable, Random r = new Random(); and then call r.nextInt(10).

检查时绝对值得out：

It would be definitely worth while to check out:

• 非静态方法无法从静态上下文中引用背后的原因是什么？

• What is the reason behind "non staticmethod cannot be referenced from a static context"?

你真的应该替换这一行，

You really should replace this line,

Random Random = new Random(); 

有这样的东西，

Random r = new Random();

如果你使用变量名作为类名，你会遇到很多问题。此外，作为Java约定，使用变量的小写名称。这可能有助于避免一些混淆。

If you use variable names as class names you'll run into a boat load of problems. Also as a Java convention, use lowercase names for variables. That might help avoid some confusion.

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