Java，非静态无法引用静态上下文 [英] Java, non-static cannot be reference to static context

问题描述

在UNI atm做Java课程，我遇到了一个骰子问题。

Doing Java course, at UNI atm, and I'm having a bit of trouble with a dice-problem.

我有以下内容：

 public class Die {
   public int eyes;
   private java.util.Random r;
   private int n;

   public Die (int n) {
     r = new Random();
     this.n = n;
   }

   public void roll() {
     eyes = r.nextInt(Die.n);
   }

编译时我得到：非静态变量n不能从静态引用上下文。我如何解决这个问题，同时从用户给定的值中随机化？

When compiling I get: non-static variable n cannot be referenced from a static context. How would I go about fixing this, whilst having it randomize from a user given value?

推荐答案

n 不是静态变量，因此您无法以静态方式引用它（ Die.n ）。

n is not a static variable, so you cannot refer to it in a static manner (Die.n).

因为它是 Die 类中的实例变量，而你在<$ c中引用它$ c>死类，您只需使用 n 而不是 Die.n 。

Since it is an instance variable in the Die class, and you are referring to it in the Die class, you can just use n instead of Die.n.

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