无法从静态上下文引用非静态变量名称 [英] non static variable name cannot be referenced from a static context

问题描述

class Singer
{
 String name;
 String album;

 public Singer(){
  name="Whitney Houson";
  album="Latest Releases";
 }

 public static void main(String[] args) 
 {
  System.out.println("Name of the singer is "+name);
  System.out.println("Album Information stored for "+album);

 }
}

当我运行此代码时，我是发现错误，表示非静态变量名称无法从静态上下文引用

When i run this code i am finding error which says that non static variable name cannot be referenced from a static context

推荐答案

这是因为变量名称和相册不存在于主过程中，因为它是静态的，这意味着它无法访问实例级成员。你需要一个Singer类的实例，如下所示：

That's because the variables name and album do not exist in the main procedure, because it's static, which means it cannot access instance-level members. You will need an instance of the Singer class, like this:

public static void main(String[] args) {
 Singer s = new Singer();
 System.out.println("Name of the singer is " + s.name);
 System.out.println("Album information stored for " + s.album);
}

但是，除非您使用公共访问修饰符声明您的姓名/专辑成员，上面的代码将无法编译。我建议为每个成员编写一个getter（getName（），getAlbum（）等），以便从封装中受益。像这样：

However, unless you declare your name/album members with a public access modifier, the above code will fail to compile. I recommended writing a getter for each member (getName(), getAlbum(), etc), in order to benefit from encapsulation. Like this:

class Singer {
 private String name;
 private String album;

 public Singer() {
    this.name = "Whitney Houston";
    this.album = "Latest Releases";
 }

 public String getName() {
     return this.name;
 }

 public String getAlbum() {
     return this.album;
 }

 public static void main(String[] args) {
     Singer s = new Singer();
     System.out.println("Name of the singer is " + s.getName());
     System.out.println("Album information stored for " + s.getAlbum());

 }

}

另一种选择是要将名称和专辑声明为静态，然后您可以按照原定的方式引用它们。

Another alternative would be to declare name and album as static, then you can reference them in the way you originally intended.

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