（Java）指定将二进制数转换为字符串时的位数（长度）？ [英] (Java) Specify number of bits (length) when converting binary number to string?

问题描述

我正在尝试将数字存储为数组中的二进制字符串，但我需要指定将其存储为多少位。

I'm trying to store a number as a binary string in an array but I need to specify how many bits to store it as.

例如，如果我需要用两位存储0我需要一个字符串00。或者1010有6位所以001010。

For example, if I need to store 0 with two bits I need a string "00". Or 1010 with 6 bits so "001010".

任何人都可以帮忙吗？

编辑：谢谢大家，我对数学/编程总体上很垃圾我已经选择了大卫的最简单的解决方案。类似于：

Thanks guys, as I'm rubbish at maths/programming in general I've gone with the simplest solution which was David's. Something like:

binaryString.append(Integer.toBinaryString(binaryNumber));
for(int n=binaryString.length(); n<numberOfBits; n++) {
                        binaryString.insert(0, "0");
}

似乎工作正常，所以除非效率很低，否则我会选择它。

It seems to work fine, so unless it's very inefficient I'll go with it.

推荐答案

使用 Integer.toBinaryString（）然后检查字符串长度并在它前面加上你想要的长度所需的零。

Use Integer.toBinaryString() then check the string length and prepend it with as many zeros as you need to make your desired length.

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