如何在屏幕捕获程序中使用Java获得超过30FPS？ [英] How to get over 30FPS using Java in a Screen Capture Program?

问题描述

我目前正在使用Java中的Robot类来记录屏幕。但是，它不能达到每秒30帧的最小值。我不会重新创建对象，并且尽可能高效，但我平均每秒只有15帧。机器人根本就没有削减它。

I'm currently using the Robot classes in Java to record the screen. However, it does not achieve the minimum of 30 frames per second. I'm not re-creating objects, and am being as efficient as I can, but I only average around 15 frames per second. Robot is simply not cutting it.

我可以用什么来捕捉屏幕？我已经尝试过Xuggle了，但我似乎无法获得足够快的捕获速度。

What can I use to capture the screen? I've tried Xuggle, but I can't seem to get that to capture fast enough either.

推荐答案

对于以下操作系统X11标准（Linux，FreeBSD，Solaris等），我们可以通过 JavaCV 和 FFmpeg ：

For operating systems following the X11 standard (Linux, FreeBSD, Solaris, etc.), we can do it this way via JavaCV and FFmpeg:

import com.googlecode.javacv.*;

public class ScreenGrabber {
    public static void main(String[] args) throws Exception {
        int x = 0, y = 0, w = 1024, h = 768; // specify the region of screen to grab
        FFmpegFrameGrabber grabber = new FFmpegFrameGrabber(":0.0+" + x + "," + y);
        grabber.setFormat("x11grab");
        grabber.setImageWidth(w);
        grabber.setImageHeight(h);
        grabber.start();

        CanvasFrame frame = new CanvasFrame("Screen Capture");
        while (frame.isVisible()) {
            frame.showImage(grabber.grab());
        }
        frame.dispose();
        grabber.stop();
    }
}

我不知道Windows或Mac OS X ，但我怀疑我们需要直接访问本机API。尽管如此， JavaCPP 可以为您提供帮助。

I don't know about Windows or Mac OS X, but I suspect we would need to access native APIs directly. Nevertheless, JavaCPP could help with that.

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