我怎么能复制这个lerping函数的反面？ [英] How could I replicate the opposite of this lerping function?

问题描述

在下面的lerping功能中，它会减慢跟随移动物体的摄像机的速度，并且当移动物体减速或停止摄像机赶上它时。我需要相反的。我需要相机移动到移动物体之前，并在物体减速/停止时减速回到物体。我似乎无法使其发挥作用。有任何想法吗？

In the lerping function below, it will slow down a camera which is following a moving object, and as the moving object slows down or stops the camera catches up to it. I need the opposite. I need the camera to move ahead of the moving object and slow down back to the object when the object slows/stops. I can't seem to make it work. Any ideas?

//this is the opposite of what I want.
float lerp = 0.1f;
Vector3 position = this.getCamera().position;
position.x += (Obj.x - position.x) * lerp;
position.y += (Obj.y - position.y) * lerp;

推荐答案

只需增加到 110％ 而不是减少到 10％

just increase to 110% instead of decreasing to 10%

float lerp = 1.1f;
position.x += (Obj.x + position.x) * lerp;
position.y += (Obj.y + position.y) * lerp;

示例：

public static void main(final String[] args)
{
    double position = 0;
    for (int i = 0; i < 100; i++)
    {
        position = (position + 10) * 1.1;
        System.out.println("position = " + position);
    }
}

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