Java8为LocalDateTime添加时间不起作用 [英] Java8 Adding Hours To LocalDateTime Not Working

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本文介绍了Java8为LocalDateTime添加时间不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我尝试过如下,但在两种情况下它都显示同一时间?我做错了。

I tried like below, but in both the cases it is showing same time? What i am doing wrong.

    LocalDateTime currentTime = LocalDateTime.now(ZoneId.of("UTC"));
    Instant instant = currentTime.toInstant(ZoneOffset.UTC);
    Date currentDate = Date.from(instant);
    System.out.println("Current Date = " + currentDate);
    currentTime.plusHours(12);
    Instant instant2 = currentTime.toInstant(ZoneOffset.UTC);
    Date expiryDate = Date.from(instant2);
    System.out.println("After 12 Hours = " + expiryDate);

当前日期时间与12小时后相同......

"Current Date" Time is showing Same as "After 12 Hours"...

推荐答案

LocalDateTime 的文档指定 LocalDateTime <的实例/ code>是不可变的,例如 plusHours

The documentation of LocalDateTime specifies the instance of LocalDateTime is immutable, for example plusHours


public LocalDateTime plusHours(长时间)

返回指定的 LocalDateTime 的副本已添加
小时数。

Returns a copy of this LocalDateTime with the specified number of hours added.

此实例不可变且不受此方法调用的影响。

This instance is immutable and unaffected by this method call.

参数:

小时 - 要添加的小时数,可能为负数

退货:

a LocalDateTime基于此日期时间添加小时数,而不是null

投掷:

DateTimeException - 如果结果超出支持的日期范围

Parameters:
hours - the hours to add, may be negative
Returns:
a LocalDateTime based on this date-time with the hours added, not null
Throws:
DateTimeException - if the result exceeds the supported date range

那么,你创建一个新的 LocalDateTime实例执行加号操作时,需要按如下方式赋值:

So, you create a new instance of LocalDateTime when you execute plus operation, you need to assign this value as follows:

LocalDateTime nextTime = currentTime.plusHours(12);
Instant instant2 = nextTime.toInstant(ZoneOffset.UTC);
Date expiryDate = Date.from(instant2);
System.out.println("After 12 Hours = " + expiryDate);

我希望它对您有所帮助。

I hope it can be helpful for you.

这篇关于Java8为LocalDateTime添加时间不起作用的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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