帮助将Int转换为二进制Python 3而不使用（“bin（）”） [英] help to convert Int to binary Python 3 without using("bin()")

问题描述

我很擅长编程所以我来这里为你专业人士帮助我摆脱，如何制作一个程序转换整数（从用户输入）到二进制代码，不使用bin（）函数。



这是我自己开始做的事情：

Hi,

I'm pretty new to programation so I came here for you "pros" to help me fidding out, how to make a program that convert integer(from the user input) to a binary code, without using the bin() function.

Here is what I started to do by myself:

nDecimal = eval(input("entrer un décimal positif :"))
print("Le nombre décimal entrer est:", nDecimal)

#transformation into binairy:


while nDecimal != 1 or 0:
    for i in nDecimal:
        i = nDecimal % len(nDecimal)
        if i > 1 or 0:
            i += 1
        else:
            print("votre nombre", nDecimal, "en binaire est:", i)
            break

当然代码不起作用:(。我试图使用用户输入的模数并添加到它1直到 nDecimal不再可分割。



Ps：对不起我的英语。

Of course that code doesn't work :(. I tried to use the modulo of the user input and add to it 1 until the "nDecimal" is not divisible anymore.

Ps: Sorry for my sh*tty english.

推荐答案

要将十进制数转换为二进制数，您需要将剩余的连续除以2，然后反向打印。例如，数字13是

To convert a decimal number to its binary equivalent you need to take the remainder of successively dividing by 2, and print in reverse. For example the number 13 is

13 / 2 = 6 rem 1
 6 / 2 = 3 rem 0
 3 / 2 = 1 rem 1
 1 / 2 = 0 rem 1
      binary = 1101

尝试

Try

nDecimal = eval(input("entrer un décimal positif :"))
print("Le nombre décimal entrer est:", nDecimal)
nbin=[]
while nDecimal > 0:
    value = int(nDecimal % 2)
    # print (value)
    nDecimal = int(nDecimal / 2)
    nbin.append(value)
nbin.reverse()
print("Le nombre binaire est", end=": ")
for x in nbin:
    print(x, end='')

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