如何通过指定列求和 [英] How to sum the column order by specify column
本文介绍了如何通过指定列求和的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
在我的表中有以下内容
In my table has following
sno date desc amt credit debit total
2 08/02/2012 PURCHASE A/C 23 34500.00 0.00
2 08/02/2012 SOMU 23 0.00 34500.00 NULL
3 08/02/2012 SALES A/C 24 0.00 6000.00 NULL
3 08/02/2012 DEVA 24 0 0.00 NULL NULL
4 08/03/2012 SBI 14 0.00 1000.00 NULL NULL
4 08/03/2012 Cash A/c 14 1000.00 0.00 NULL
4 08/03/2012 Cash A/c 14 1000.00 0.00 NULL
4 08/03/2012 Cash A/c 14 1000.00 0.00 NULL
我想按日期对借方金额"和贷方金额"组求和?
I want to sum of the Debit amount and Credit amount group by date how to do it?
sno date desc amt credit debit total
2 08/02/2012 PURCHASE A/C 23 34500.00 0.00
2 08/02/2012 SOMU 23 0.00 34500.00 NULL
3 08/02/2012 SALES A/C 24 0.00 6000.00 NULL
3 08/02/2012 DEVA 24 6000.00 0.00 NULL NULL
4 08/02/2012 Total null 69000 6000 null
5 08/02/2012 balance null 9000 null null
4 08/03/2012 SBI 14 0.00 1000.00 NULL NULL
4 08/03/2012 Cash A/c 14 1000.00 0.00 NULL
4 08/03/2012 Cash A/c 14 1000.00 0.00 NULL
4 08/03/2012 Cash A/c 14 1000.00 0.00 NULL
5 08/03/2012 Total null 4000 0.00 null
6 08/03/2012 balance null 4000 0.00 null
如何按日期获取订单的总金额.
谢谢
How to get the total amount for order by date.
Thank you
推荐答案
从表中选择日期，总和(借方)，总和(贷方)
按日期分组
select date, sum(debit), sum(credit) from table
group by date
With CTE_Test
as
(select sno,[date],[desc],amt,creit,debit,Total,Row_number() over (PARTITION By date order by sno) as rowno
from temp_Table
union all
Select MAX(sno)+1,[date],'Total',null,SUM(creit),SUM(Debit),Null,1 from temp_table group by [date]
union all
Select MAX(sno)+2,[date],'Balance',null,SUM(creit)-SUM(Debit),null,Null,1 from temp_table group by [date])
Select * from cte_test order by date,sno
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