将向量转移到函数 [英] Transfer vector to function

问题描述

我有一个在其上使用vector的c ++代码.我想从主函数的另一个函数中调用此向量.

Hi,
I have one c++ code that used vector on that. I want call this vectors from another function from main function.

int main ()
{
  vector<double> ld_12;
 vector<double> ld_24;
double d=f0(ld_12,ld_24);
.
.
.
return;
}
double f0(double *a0,double*a1){
.
.
.
}

我想知道如何在标头f0中调用两个向量:
双重f0(double * a0，double * a1)

此致

I want know how call two vectors in header f0:
double f0(double *a0,double*a1)

Regards,

推荐答案

int main ()
{
    vector<double> ld_12;
    vector<double> ld_24;
    double d = f0(&ld_12, &ld_24);

// ...

    return;
}

double f0(vector<double>* a0, vector<double>* a1)
{
    double dValue = 0.0;

    dValue = a0->at(0);

// ...

    return  dValue;
}

更多代码

More code

int main()
{
  vector<double> ld_12;
  vector<double> ld_24;

  /// ... i assume there is some code to fill the 2 vectors

  double d = f0(ld_12, ld_24);

  return 0;
}

// The & means the vectors are modifyable.
double f0 ( vector<double>& a0, vector<double>& a1 )
{
  double value = 0.0;

  // get the size of the vectors.
  size_t a0_size = a0.size();
  size_t a1_size = s1.size();

  // do something.
  return value;
}
</double></double></double></double>

2个选项:

1-如果可能，请重构代码以使f0接收向量而不是数组.
2-调用f0，例如:

2 options :

1- If possible, refactor the code to have f0 receive vectors instead of arrays.
2- call f0 like :

f0( &ld_12[0], &ld_24[0] );

之所以行之有效，是因为该标准告诉我们，向量是在连续内存中分配的(例如arrary).

另外，不要忘记将2个数组的大小传递到您的f0函数.

This works because the standard tells us that the vector is allocated in continuous memory (like an arrary).

Also, don''t forget to pass the size of the 2 arrays somewhere to your f0 function.

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