将int转换为十六进制值 [英] convert int to hex value

问题描述

我想将int值转换为十六进制值.十六进制值存储在int变量中.
假设我的int = 22；我想将22转换为十六进制值(16-十六进制值22).并且最后16位存储在任何int变量(int b)中.

I want to convert int value into hex value. And hex value is stored in int variable.
suppose I have int a = 22; and i want to convert 22 into hex value(16- hex value of 22). And at the last 16 is stored into any int variable(int b).

推荐答案

变量都在内部存储为二进制，因此如果要查看的值十六进制，纯粹是人类可读的表示形式.

例如:

Variables are all internally stored as binary, so if you want to view a value as hex, its purely a human readable representation.

For example:

int a = 22;
CString hex_a;
hex_a.Format("%X", a); //<-- this will contain hex 16, but only as text

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