如何在内核模块中使用sysfs? [英] How to use sysfs inside kernel module?

问题描述

在用户空间中，我只能echo noop > /sys/block/sda/queue/scheduler.

In userspace I can just echo noop > /sys/block/sda/queue/scheduler.

如何在内核模块中执行相同的操作?

How to do the same inside a kernel module?

我希望这样的东西(伪代码):

I expect something like this (pseudocode):

struct dentry* e = sysfs_get_root();
vfs_path_lookup(e, ????, "block/sda/queue/scheduler", ???);
????;
struct something* q = ????;
????->store(q, "noop", 1);
/* some cleanup */

如何正确实施?

我的内核模块仅注册SysRQ处理程序，并应在触发SysRQ时配置io调度程序(由于io-scheduler错误，此时可以挂载用户空间程序)

My kernel module just registers SysRQ handler and should configure the io scheduler when that SysRQ is triggered (userspace programs can be hung at that time because of the bad io-scheduler)

推荐答案

无法正确实现.如果您仍然想这样做，并且 了解为什么它是一个坏主意(tm)的原因，请参见此文章

There is just no way to implement it properly. If you want to do it anyway, and also understand the reason why it is a Bad Idea (tm), see this article

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