Kotlin属性与吸气剂.我可以不指定初始值吗? [英] Kotlin property with getter. Can I not specify an initial value?
问题描述
我想创建一个单例类,但是不幸的是,Android几乎所有内容都需要Context,因此我需要它来创建实例.所以我只是假设用户名为init()
,然后返回该实例.如下所示,如果_instance
为null,则将引发异常,因此get
方法不能返回null.
I want to create a singleton class, but unfortunately, Android needs Context for almost anything so I need it to create an instance. So I just assumed the user called init()
, and then return the instance. As you see below, if the _instance
is null, an exception will be thrown, so the get
method cannot return null.
但是Kotlin说我必须初始化instance
.事实是,没有上下文就无法创建MyClass.因此,我不想指定初始值.我该怎么办?
But Kotlin says I must initialise instance
. The things is, that MyClass cannot be created without a context. So I would like not to specify an initial value. How can I do that?
companion object
{
protected var _instance:MyClass? = null;
fun init(context:Context)
{
_instance = MyClass(context)
}
var instance:MyClass //<---This causes a compile error.
get()
{
if(_instance==null) throw RuntimeException("Call init() first.");
return _instance!!;
}
}
推荐答案
将var
更改为val
,它应该可以工作:
Change the var
to val
and it should work:
....
val instance: MyClass
....
可变属性(var
)不仅假定使用getter,而且假定使用setter.由于您未提供设置器,因此将生成默认设置器set(value) { field = value }
.尽管在这种情况下毫无用处,但默认的setter使用field
,因此需要对其进行初始化.
A variable property (var
) not only assumes a getter, but also a setter. Since you provided no setter, a default one was generated set(value) { field = value }
. Despite is uselessness in this situation, the default setter uses field
, thus requires its initialization.
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