如何为C ++程序从MSYS Makefile定义路径? [英] How do I define a path from an MSYS Makefile for a C++ program?

问题描述

我的问题:在我同时在MSYS和MSYS2环境中使用的Makefile中，我知道一个路径PYTHON_ROOT_DIR，该路径将在C ++程序的编译时使用.问题是PYTHON_ROOT_DIR在称为posix样式路径的Makefile中，例如/mingw64/bin，在C ++程序中，其格式应为"C:\\prog64\\msys64\\mingw64\\bin".另一个挑战是，取决于配置变量PYTHONMAJOR，路径应为宽字符或普通字符.

My problem: in a Makefile which I use in both the MSYS and the MSYS2 environment I know a path, PYTHON_ROOT_DIR, which shall be used at compilation time in a C++ program. Problem is PYTHON_ROOT_DIR is in the Makefile known as posix style path such as /mingw64/bin, where in the C++ program it shall have a form like "C:\\prog64\\msys64\\mingw64\\bin". Additional challenge is that depending on a configuration variable PYTHONMAJOR the path shall be wide characters or normal characters.

我的问题:我如何在Makefile中解决此问题，而无需在msys或msys2环境中安装其他程序/脚本?

My question: how do I solve this in the Makefile without a need to install additional programs/scripts in the msys or msys2 environments?

推荐答案

部分问题在

Part of the question is addressed in msys path conversion (or cygpath for msys?), namely how to convert a msys style path to a windows style path. My full solution in the Makefile is:

ifeq ($(PYTHONMAJOR),3)
    L=L
endif
DEFINES += -DPYTHON_ROOT_DIR=$(L)'"'$(shell (cmd //c echo $(PYTHON_ROOT_DIR)) | sed 's|/|\\\\\\\\|g')'"'

定义具有正确路径的预处理器符号PYTHON_ROOT_DIR.

which defines the preprocessor symbol PYTHON_ROOT_DIR with the proper path.

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