函数不断返回NaN [英] function keeps returning NaN

问题描述

大家好，我知道NaN(让我说我知道首字母缩写代表Not a Number)是什么，但我不明白C ++为什么返回它-以下是数学常数e的近似值-使用调试器时函数评估良好，是在写入控制台时返回NaN

Hi guys i know what NaN(let me say i know the acronym stands for Not a Number) is but i don't understand why C++ returns it - The following is the approximation of the mathematical constant e - When using the debugger the functions evaluate fine, it's when writing to the console that it returns NaN

感谢您的反馈意见

double Factorial(int k)
{
    if(k == 0)
        return 1;

    int value = 1;
    for(int i = k; i > 0; i--)
        value *= k;
    return value;
}

double e(int p)
{
    double value = 0.0;

    for(int i = 0; i < p; i++)
    {
        value += 1/Factorial(i);
    }
}

推荐答案

您不会在e函数中返回值.

You don't return a value in your e function.

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